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xxTIMURxx [149]
2 years ago
8

Suppose that shifting into third gear decreased the engine speed (rpm) while increasing the tractor speed (mph). What would be t

he effect of this change?
a). both area rate and flow rate would increase
b). area rate would increase and flow rate decrease
c). arear rate would decrease and flow rate increase
d). both area rate and flow rate would increase
Mathematics
1 answer:
Vladimir [108]2 years ago
8 0

What would be the effect of this change is: a). both area rate and flow rate would increase.

<h3>Shifting of gear</h3>

Assuming a driver shift into third gear in which there was reduction in the engine speed while on the other hand the tractor speed increase.

The effect of the change will result in the increase in area rate as well as the  flow rate.

Therefore the correct option  is<em> </em>A.

Learn more about Shifting of gear here:brainly.com/question/18192699

#SPJ1

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Please help me asap!!
Bess [88]

Answer:

x = 14

Step-by-step explanation:

The polygon given has 6 sides

Sum of interior angles of a 6-sided polygon = 180(n - 2)

substitute n = 6 into 180(n - 2)

Sum of the polygon = 180(6 - 2) = 720°

Thus:

10x + 8x - 16 + 12x - 8 + 7x + 2 + 9x + 4 + 6x + 10 = 720

Add like terms

52x - 8 = 720

52x = 720 + 8

52x = 728

x = 728/52

x = 14

3 0
2 years ago
Marie can find the volume of a cube by using the formula V = s³, where s represents the side length of the cube. If Marie's cube
UNO [17]

Answer:

15.625 cm^3

Step-by-step explanation:

V=2.5^{3} \\V=2.5*2.5*2.5\\V=6.25*2.5\\V=15.625 cm^{3}

7 0
3 years ago
SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

6 0
3 years ago
No entendi lpM explicen
LuckyWell [14K]
No able engles? Don’t know if i spelt that right but
3 0
3 years ago
I need how you found the answers?
lara31 [8.8K]

Answer:

2x + 6 = -18

x + 1 = -11

3x = -36

Step-by-step explanation:

First find the solution! Then you can create your own equations

2x+9=-15

2x=-24

x=-12

Thus u need solutions with:

x = -12

Knowing the equation of a line as:

y = mx + b

we can can start by making y = -12 (our solution)

mx + b = -12

Now we can pick a value for m and b by adding and miltiplying on both sides

We do this to keep both sides equal.

if we make m = 2 and b = 3:

2x + mb = -12*m + 2b

2x + 6 = -24 + 6

2x + 6 = -18

Solving this we also get x = -12, as we expect.

An alternative way to think about it is to imagine that we start with a simple equation and make it more complex. We have our solution:

x = -12  => lets add a b value!

x + b = -12 + b => Lets add a slope (m)

xm + bm = -12m + bm

Giving values for this can give you multiple equation of the same solution.

General Formula:

m(x+b) = m(y+b)

mx + bm = my + bm

8 0
3 years ago
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