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xxTIMURxx [149]
2 years ago
8

Suppose that shifting into third gear decreased the engine speed (rpm) while increasing the tractor speed (mph). What would be t

he effect of this change?
a). both area rate and flow rate would increase
b). area rate would increase and flow rate decrease
c). arear rate would decrease and flow rate increase
d). both area rate and flow rate would increase
Mathematics
1 answer:
Vladimir [108]2 years ago
8 0

What would be the effect of this change is: a). both area rate and flow rate would increase.

<h3>Shifting of gear</h3>

Assuming a driver shift into third gear in which there was reduction in the engine speed while on the other hand the tractor speed increase.

The effect of the change will result in the increase in area rate as well as the  flow rate.

Therefore the correct option  is<em> </em>A.

Learn more about Shifting of gear here:brainly.com/question/18192699

#SPJ1

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Elodia [21]

Answer:

4

the fourth expression is a rational

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3 years ago
Read 2 more answers
5 ordered pairs of y=2x+5 please help its due tomorrow
dybincka [34]
(0,5) (-3, -1) (1, 7) (2, 9) (-5, -5)
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3 years ago
It would be nice if I get some help with these 2 things
Stella [2.4K]
Thing 1
A. You can set up a proportion by dividing how much of something there is by the original. (This probably doesn't make much sense but I hope you can understand it from the answer to the problem below!)
B.First, do 168/21 to see how many more times he put flour in. 
168/21= 8
Then to find out the milk in the same proportion do the number (in this case 8) times the original of the thing you wan to find out. 
8x9=72
72 tablespoons of milk are needed for 168 cups of flour in this adapted recipe.

Thing 2
24/36=8y
To solve any equation, you want to have letters on one side and numbers on the other, so...
-8 from both sides...
(24/36)-8=y
24/36=0.6 
y=(0.6-8)
y=-7.4

Hope this helps :)
5 0
3 years ago
a port and a radar station are 2 mi apart on a straight shore running east and west. a ship leaves the port at noon traveling no
Rom4ik [11]

Answer:

The rate of change of the tracking angle is 0.05599 rad/sec

Step-by-step explanation:

Here the ship is traveling at 15 mi/hr north east and

Port to Radar station = 2 miles

Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles

Therefore the ship, port and radar makes a triangle with sides

2, 7.5 and x

The value of x is gotten from cosine rule as follows

x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04

x = 6.25 miles

By sine rule we have

\frac{sin A}{a} = \frac{sin B}{b}

Therefore,

\frac{sin 45}{6.25} = \frac{sin \alpha }{7.5}

α = Angle between radar and ship α

∴ α = 58.052

Where we put

\frac{sin 45}{6.25} = \frac{sin \alpha }{x} to get

\frac{x}{6.25} = \frac{sin \alpha }{sin 45} and differentiate to get

\frac{\frac{dx}{dt} }{6.25} = cos\alpha\frac{\frac{d\alpha }{dt}  }{sin 45}

\frac{15sin45 }{6.25cos\alpha } =\frac{d\alpha }{dt}  }= 3.208 degrees/second = 0.05599 rad/sec.

6 0
3 years ago
Ssignment
Vladimir [108]
Not completely sure what you’re asking but y=3.5x has the sharpest rise and out of the bottom four y=3x does
5 0
3 years ago
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