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prisoha [69]
3 years ago
15

Plsssssssssssssssssssss help me fast

Mathematics
2 answers:
zlopas [31]3 years ago
5 0

Answer:

The answer is 95cm2

Step-by-step explanation:

A=b×h

=19×5

= 95 cm2

please mark me the brainliest

jasenka [17]3 years ago
4 0
Area of a parallelogram=base×height
Area=19×5=95cm²

Hope my answer helped u :)
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Select the correct answer. Simplify the expression.<br> (see the screenshot)
Sliva [168]

Answer:

Option D

Step-by-step explanation:

Given expression has been given as,

\sqrt[5]{224x^{11}y^8}

\sqrt[5]{224x^{11}y^8}=\sqrt[5]{2\times 2\times 2\times 2\times 2\times 7(x^{11})(y^8)}

                 =\sqrt[5]{(2^5)\times (7)(x^{10}\times x)(y^5\times y^3)}

                 =2^{\frac{5}{5}}\times 7^{\frac{1}{5}}\times x^{\frac{10}{5}}\times x^{\frac{1}{5}}\times y^{\frac{5}{5} }\times y^{\frac{3}{5} }

                 =2\times 7^{\frac{1}{5}}\times x^2\times y\times x^{\frac{1}{5} }\times y^{\frac{3}{5} }

                 =2x^2y\sqrt[5]{7xy^3}

Option D will be the answer.

7 0
3 years ago
-k2-(3k-5n)+6n; k=-3 and n=-4
Anna11 [10]
If you are evaluating the answer is -41
5 0
2 years ago
If a case of 24 cans of peaches costs $7.50 how much does each can cost to the nearest cent
valina [46]
30 cents is the answer
3 0
3 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
Read 2 more answers
What is the integer closest to the square root of 17
Alex Ar [27]

Answer:

4

Step-by-step explanation:

\sqrt{16} = 4

7 0
3 years ago
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