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Umnica [9.8K]
3 years ago
14

Can someone please explain how to do these two problems?

Mathematics
1 answer:
Alexxx [7]3 years ago
3 0

Step-by-step explanation:

using algebra create a expression with the volume and the sides

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If it takes 5 hours to do 2/3 of a job, how long will it take to complete a job?
VLD [36.1K]
I set it up as a ratio with hours on the top and the fraction of the job on the bottom.  It looks like this: 5/(2/3) / x/1, because 1 is the whole job if 2/3 is only a fraction of it.  Cross multiplying gives you 2/3x = 5. Solving for x gives you that it will take 7.5 hours to complete a whole job if it takes 5 hours to complete 2/3 of it.
7 0
3 years ago
How far is the little guy from the flagpole (assuming a right angle between the flagpole and the ground)? Explain how you got yo
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Answer:

9

Step-by-step explanation:

a^2 + b^2 = h^2

15^2= 12^2 + b^2

225=144+b^2

81=b^2

9

7 0
3 years ago
Solve: 92x + 1 = 93x – 2
vichka [17]

Answer:

x equals 3 :) if i helped, please give brainliest!

Step-by-step explanation:

6 0
3 years ago
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The equation's X-y= 2, -2y=-2, X+ y = 2, and x+2y=-2 are shown on the graph below.
ziro4ka [17]

Answer:

A.) x-y=2 and x+2y=-2

Step-by-step explanation:

For option A, we have:

x-y=2

x+2y=-2

Subtract the first equation from the second, to get:

2y--y=-2-2

This implies that:

2y+y=-2-2

Simplify to get:

3y=-4

Divide both sides by 3 to get:

y =  -  \frac{4}{3}  =  - 1.3

We substitute y=-1.3 into the first equation to get:

x--1.3=2

x+1.3=2

x=2-1.3

x=0.7

The solution is (0.7,-1.3), which is approximately (0.7, -1.4)

By inspection, all the other factors have solutions not close to (0.7, -1.4)

3 0
3 years ago
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Which expression is equivalent to (sqrt3 + i)^3?
Anarel [89]

Express √3 + i in polar form:

|√3 + i| = √((√3)² + 1²) = √4 = 2

arg(√3 + i) = arctan(1/√3) = π/6

Then

√3 + i = 2 (cos(π/6) + i sin(π/6))

By DeMoivre's theorem,

(√3 + i)³ = (2 (cos(π/6) + i sin(π/6)))³

… = 2³ (cos(3 • π/6) + i sin(3 • π/6))

… = 8 (cos(π/2) + i sin(π/2))

… = 8i

4 0
3 years ago
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