Hie!! I will be solving the questions in the sequence of the attachments.
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4. As line SU and TV are intersecting each other at O.
A.T.Q, ∠UOV = (7x - 4)°
∠SOT = 87°
Then, ∠UOV = ∠SOT {Vertically Opposite Angles}





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5. radius = 17ft
circumference of circle = 2πr


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3. ∠1 and ∠2 - add to 180 (linear pair)
∠1 and ∠3 - equal (Vertically Opposite Angles)
∠3 and ∠4 - add to 180 (linear pair)
∠2 and ∠4 - equal (Vertically Opposite Angles)
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2. 160° + (6x - 16)° = 180° (linear pair)






The density of the gold is 772.8 kilograms\cubic meters
Answer:
Part a) The radii are segments AC and AD and the tangents are the segments CE and DE
Part b) 
Step-by-step explanation:
Part a)
we know that
A <u>radius</u> is a line from any point on the circumference to the center of the circle
A <u>tangent</u> to a circle is a straight line which touches the circle at only one point. The tangent to a circle is perpendicular to the radius at the point of tangency.
In this problem
The radii are the segments AC and AD
The tangents are the segments CE and DE
Part b)
we know that
radius AC is perpendicular to the tangent CE
radius AD is perpendicular to the tangent DE
CE=DE
Triangle ACE is congruent with triangle ADE
Applying the Pythagoras Theorem

substitute the values and solve for CE





remember that
CE=DE
so

Answer:
(√366 - 3)/24
Step-by-step explanation:
Given the following:
cos∝ = √3/8 and sinβ = √3/3
Sin(∝-β) = sin∝cosβ - cos∝sinβ
Get sin∝
Since cos∝ = √3/8
adj = √3
hyp = 8
opp = √8² - (√3)²
opp = √64 - 3
opp = √61
Recall that sin∝ = opp/hyp
sin∝ = √61/8
Get cosβ
Since sinβ = √3/3
opp = √3
hyp = 3
adj =√3² - (√3)²
adj = √9-3
adj = √6
Recall that cosβ = adj/hyp
cosβ = √6/3
Substitute the gotten values into the formula
Sin(∝-β) = sin∝cosβ - cos∝sinβ
Sin(∝-β) = ( √61/8)(√6/3)- (√3/8)(√3/3)
Sin(∝-β) = √366/24 - √9/24
Sin(∝-β) = (√366 - 3)/24
Answer:
-7
Step-by-step explanation:
3 v + 2 x
3 ( - 1) + 2 ( -2)
-3 - 4
-7