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3 years ago

How many solutions does the equation 4x + 8 = −2 − 2 + 5x have?

Mathematics

1 answer:

alisha [4.7K]3 years ago

8 0

B. One (12) I think.

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A diagonal support beam is attached to the gate of a fence as shown. Which angles must be congruent in order for the top and bot

statuscvo [17]

Where is it shown? You need to attach a picture or something.

5 0

3 years ago

I don’t know how to do this. Ignore my work it’s probably wrong. Please help.

wariber [46]

Check the picture below.

well, we start off by making a table of values for the function, with a few "t" values, as you see in the picture, then graph those points to get the graph.

at t = 0, h(0) = 98, and at t = 1, h(1) = 82, so it went from 98 to 82, for a difference of 16.

at t = 1, h(1) = 82, and at t = 2 h(2) = 34, so it went from 82 to 34, for a difference of 48.

does it fall the same distance on both intervals? well, they're different, so nope.

6 0

3 years ago

I need help I’m stuck

cluponka [151]

Answer:

Step-by-step explanation:

5 0

3 years ago

Add.

Ann [662]

Answer:

17. +5-2-1=+2

18. -7-6-2=15

19. +11-9-4=-2

20.+4-8+6=+2

6 0

3 years ago

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0

3 years ago