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faltersainse [42]
3 years ago
8

33 1/3% of what number is 21

Mathematics
2 answers:
frutty [35]3 years ago
6 0
It would be 63, because 33 1/3% is the equivalent of 1/3,
21x3 = 63
Nina [5.8K]3 years ago
3 0
Recall that 33 1/3% is equal to 1/3.

x/3 = 21

Multiply both sides by 3.

x = 63
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a probability experiment consists of fair eight sided die find the probability of rolling number greater than 4 ​
Lunna [17]

Answer:

Probability[Number greater than 4] = 1/2

Step-by-step explanation:

Given:

Total side of die = 8

Find:

Probability[Number greater than 4]

Computation:

Number greater than 4;

[5,6,7,8]

Total number greater than 4 = 4

Probability[Number greater than 4] = Total number greater than 4 / Total side of die

Probability[Number greater than 4] = 4 / 8

Probability[Number greater than 4] = 1/2

3 0
3 years ago
Find the equation of a line that contains the points (−3,−1) and (−4,−7). Write the equation in slope-intercept form
ikadub [295]

Answer:

  y = -8x -25

Step-by-step explanation:

The 2-point form of the equation of a line is useful when you are given 2 points.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (7 -(-1))/(-4 -(-3))(x -(-3)) +(-1)

  y = 8/-1(x +3) -1

  y = -8x -25

7 0
3 years ago
A local sorority sold hot dogs and bratwursts at the spring fling picnics. The first day they sold 8 dozen hot dogs and 13 dozen
kicyunya [14]

Answer:

1 hot dog costs $0.75

1 bratwurst costs $1.35

Step-by-step explanation:

Let x and y be the price per dozen of hot dogs and bratwursts respectively.

The first day they sold 8 dozen hot dogs and 13 dozen bratwursts for ​$282.60

8x + 13y = 282.60

The second day they sold 10 dozen hot dogs and 15 dozen bratwursts for a total of ​$333.00

10x + 15y = 333

and we have the linear system

<em>8x + 13y = 282.60 </em>

<em>10x + 15y = 333 </em>

which can be written in matrix form as

\bf \left(\begin{array}{cc}8&13\\10&15\end{array}\right)\left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{c}282.60\\333\end{array}\right)

The solution would be given by

\bf \left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{cc}8&13\\10&15\end{array}\right)^{-1}\left(\begin{array}{c}282.60\\333\end{array}\right)

We have  

\bf \left(\begin{array}{cc}8&13\\10&15\end{array}\right)^{-1}=\left(\begin{array}{cc}-3/2&13/10\\1&-4/5\end{array}\right)

hence

\bf \left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{cc}-3/2&13/10\\1&-4/5\end{array}\right)\left(\begin{array}{c}282.60\\333\end{array}\right)=\left(\begin{array}{c}9\\ 16.2\end{array}\right)

Now,

if a dozen hot dogs cost $9, 1 hot dog costs 9/12 = $0.75

if a dozen bratwursts cost $16.2, 1 bratwurst costs 16.2/12 = $1.35

4 0
3 years ago
More than half of the moon is visible from Earth; light appears to be increasing​
wlad13 [49]

Answer:

cool

Step-by-step explanation:

whats ur question about it?

8 0
3 years ago
Kim took out a $55,000 loan for college. She is borrowing money from two banks. Bank A charges an interest rate of 8%, and Bank
stellarik [79]
Kim's Loan:
Let A =  amount borrowed from bank A.
Let B =  amount borrowed from bank B.

The total loan is $55,000.
Therefore
A + B = 55000                  (1)

Bank A charges 8% interest. The interest after 1 year is 0.08A.
Bank B charges 11% interest. The interest after 1 year is 0.11B.
Total interest after 1 year is $5,000.
Therefore
0.08A + 0.11B = 5000      (2)

From (1), obtain
B = 55000 - A                  (3)

Substitute (3) into (2).
0.08A + 0.11(55000 - A) = 5000
0.08A + 6050 - 0.11A = 5000
-0.03A = -1050
A = -1050/-0.03 = 35000

Answer:  Kim borrowed $35,000 from bank A.

Jack's Loan.
A = loan from bank A.
B = loan from bank B.
The total loan is $10,000.
Therefore
A + B = 10000                  (4)

Bank A charges 5% interest and bank B charges 6% interest.
Total interest after 1 year is $530, therefore
0.05A + 0.06B = 530       (5)

From (4), obtain
B = 10000 - A                       (6)

Substitute (6) into (5).
0.05A + 0.06(10000 - A) = 530
0.05A + 600 - 0.06A = 530
-0.01A = -70
A = -70/-0.01 = 7000

Answer: Jack borrowed $7,000 from bank A.
3 0
4 years ago
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