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2 years ago

Find the values, if any, of the boolean variable x that satisfy these equations. x .1=0

Mathematics

1 answer:

Evgen [1.6K]2 years ago

6 0

The value of the boolean variable x is 0

<h3>How to determine the value of x?</h3>

The boolean equation is given as:

x . 1 = 0

The above means that:

x and 1 = 0

The law of the and operator is that;

The output is 0 if both inputs are different.

One of the inputs is 1.

So, the other input is 0

Hence, the value of x is 0

Read more about boolean variable at:

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Help Pls! I need this fast!

lesya [120]

Answer: 36

Step-by-step explanation:

$\overline{AB} \cong \overline{BC}$ (Triangle ABC is isosceles)

$m\angle CAB=m\angle CBA=30^{\circ}$ (base angles of an isosceles triangle are congruent)

$\angle MCB=90^{\circ}$ (In triangle CMB, angles in a triangle add to 180 degrees)

$\angle ACM=30^{\circ}$ (triangle sum theorem)

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2 years ago

Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm

Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 6, \sigma = 0.2$

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6-6}{0.2}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X 5.8.

X = 6.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 5.8

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$