Please help me find the answer.
1 answer:
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Let x be the original price,
Answer: $32
Answer:
- <em><u>Option A: 0.484</u></em>
Explanation:
The amount of <em>animal waste</em> one <em>zoo</em> is diposing daily is approximately <em>normal </em>with:
- <em>mean</em>, μ = <em>348.5 lbs</em>
- <em>standard deivation</em>, σ = <em>38.2 lbs</em>
<em>The proportion of waste over 350 lbs</em> may be found using the table for the area under the curve for the cumulative normal standard probability.
First, <u>find the z-score </u>for 350 lbs:
There are tables for the cumulative areas (probabilities) to the left and for the cumulative areas to the right of the z-score.
You want the proportion of the days when the z-score is more than 0.04; then, you can<u> use the table for the values to the rigth of z = 0.04.</u>
From such table, the area or probability is 0.4840.
The attached image shows a portion of the table with that value: it is the cell highlighted in yellow.
Hence, the answer is the option (A) 0.484.
