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Talja [164]
3 years ago
10

Please help, i do not get this.

Mathematics
1 answer:
Artyom0805 [142]3 years ago
3 0

Answer:

k(x) = |x - 4| - 2

Step-by-step explanation:

So we know that k(x) is shifted 4 untis to the right and 2 units down. In an absolute value function, the value you move to the left will be positive and the value you move to the right will be negative. Since we are moving to the right, our value will be negative.

When you shift the function up or down, you will either subtract or add that value out side the absolute value. Since we are shifting down 2 units, that means we will be subtracting by 2.

Best of Luck!

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Rewrite the expression x^3+10x^2+13x+39/x^2+2x+1 in the form of q(x)+r(x)/b(x)
natima [27]

\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}

x^3=x\cdot x^2, and x(x^2+2x+1)=x^3+2x^2+x. Subtracting this from the numerator gives a remainder of

(x^3+10x^2+13x+39)-(x^3+2x^2+x)=8x^2+12x+39

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(8x^2+12x+39)-(8x^2+16x+8)=-4x+31

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3 years ago
Point Q' is the image of Q(5, -3) after a translation down 2 units and right 4 units. What are the coordinates of Q'?
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Step-by-step explanation:

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For more on volume check out;

brainly.com/question/12595431

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