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IRISSAK [1]
2 years ago
5

Find the greatest common factor of these two expressions. 28y^7x^2 and 8y^8v^4x^6

Mathematics
1 answer:
Montano1993 [528]2 years ago
3 0

Answer:

4y⁷x²

Step-by-step explanation:

<h3>Finding GCF:</h3>

    Prime factorize each expression.

28y⁷x² = 2 * 2 * 7 * y⁷ * x²

8y⁸v⁴x⁶ = 2 * 2 * 2 * y⁸ * v⁴ * x⁶

GCF = 2 * 2 *y⁷*x²

        = 4y⁷x²

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5 0
3 years ago
(-1/3) to the power of five?
Bumek [7]

\bf \left( -\cfrac{1}{3} \right)^5\implies \left( -\cfrac{1}{3} \right)\left( -\cfrac{1}{3} \right)\left( -\cfrac{1}{3} \right)\left( -\cfrac{1}{3} \right)\left( -\cfrac{1}{3} \right)\implies -\cfrac{1^5}{3^5}\implies -\cfrac{1}{243}


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8 0
4 years ago
Sean b= 5,79; c= 10,4,el angulo A= 54,46°, el angulo C mide ?
Rzqust [24]

Answer:

C \approx 91.732^{\circ}

Step-by-step explanation:

(This exercise is presented in Spanish and for that reason explanation will be held in such language)

El lado restante se determina por la Ley del Coseno:

a = \sqrt{b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A}

a = \sqrt{5.79^{2}+10.4^{2}-2\cdot (5.79)\cdot (10.4)\cdot \cos 54.46^{\circ}}

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Finalmente, el angulo C se halla por medio de la misma ley:

\cos C = - \frac{c^{2}-a^{2}-b^{2}}{2\cdot a \cdot b}

\cos C = -\frac{10.4^{2}-8.466^{2}-5.79^{2}}{2\cdot (8.466)\cdot (5.79)}

\cos C = -0.030

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3 0
3 years ago
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vesna_86 [32]

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-n+m

Step-by-step explanation:

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4 0
3 years ago
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Answer:

<h3>$ 20 </h3>

Step-by-step explanation:

1week \:  = 5 \\ 4 \: weeks = x \\  \\ x = 20

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3 years ago
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