Answer:
4
Step-by-step explanation:
Given that At the pet owner’s meeting, there are 20 people who own dog, and 35people who own cat and 9 people own goldfish. Some people own both catand dog and some people own both gold fish and cat. No dog owners owngoldfish. There are twice as many people who own both goldfish and catthan people who own both dog and cat.
Total no of people =52
The venn diagram attached gives a clear picture
assuming x to be owners of both dog and cat. Then 2x is for both goldfish and cats.
Totalling all mutually exclusive we get
64-3x=52
x=4
No of owners who own both cat and dog =4
Answer:
$11040
Step-by-step explanation:
first of all the question says that $4000 were earned in a year and asks for what the new vale would be after the next 3 years with a discount rate of 8%.
If 1 year=$4000,then 3 years=$12000
100%-8%=92% (this happens because there is still a remaining amount that still has a cost to it),so 12000*92%=$11040
Answer:
Step-by-step explanation:
2.5 / 0.01 = 250 sheets in the stack....just a little division problem....thank god for calculators...lol
Answer:
F930
Step-by-step explanation:
You guys suck so much ohhhhhhhhhhhhhhhhhhhhh
<h2>
Answer with explanation:</h2>
Let
be the population mean lifetime of circulated $1 bills.
By considering the given information , we have :-

Since the alternative hypotheses is two tailed so the test is a two tailed test.
We assume that the lifetime of circulated $1 bills is normally distributed.
Given : Sample size : n=50 , which is greater than 30 .
It means the sample is large so we use z-test.
Sample mean : 
Standard deviation : 
Test statistic for population mean :-


The p-value= 
Since the p-value (0.0433834) is greater than the significance level (0.02) , so we do not reject the null hypothesis.
Hence, we conclude that we do not have enough evidence to support the alternative hypothesis that the average lifetime of a circulated $1 bill differs from 18 months.