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Ierofanga [76]
3 years ago
6

How many ducks can fit in a duck pond if there are 24 ducks and 10 lakes

Mathematics
1 answer:
kiruha [24]3 years ago
6 0
You can fit 2 in each or 3 can have some in it
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Point c has the coordinate -7 and d has the coordinate 6 on a number line. What is the distance between c and d
OLga [1]

Answer:

7

Step-by-step explanation:

7 0
3 years ago
Elena randomly chooses a number from 1 to 10. What is the probability she chooses a number greater than 5?
zepelin [54]

ANSWER

P(E)=\frac{1}{2}

EXPLANATION

From the given information, Elena chooses a number from 1 to 10.

The sample space is

S={1,2,3,4,5,6,7,8,9,10}

n(S)=10

The numbers greater than 5 are:

E={6,7,8,9,10}

n(E)=5

The probability that, she chooses a number greater than 5 is:

P(E) =  \frac{n(E)}{n(S)}

Substitute the values,

P(E) =  \frac{5}{10}

P(E) =  \frac{1}{2}

5 0
3 years ago
Please help with this!!! 25 points and i'll mark you brainliest!!! Show how you got answer!!!
HACTEHA [7]

Answer:

17.9°

Step-by-step explanation:

From trigonometry:

Opposite = 14

Adjacent = x

theta = 38°

hence;

tan theta = opposite/ adjacent

tan38° = 14/x

x = 14/tan38°

x = 17.9°

6 0
3 years ago
(8√2 - 5) (9√5 +6√10)<br> Simplify
salantis [7]

Answer:

42 (square root>) 10 + 51 (square root>) 5

Step-by-step explanation:

5 0
3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
2 years ago
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