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3 years ago

How many ducks can fit in a duck pond if there are 24 ducks and 10 lakes

Mathematics

1 answer:

kiruha [24]3 years ago

6 0

You can fit 2 in each or 3 can have some in it

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Point c has the coordinate -7 and d has the coordinate 6 on a number line. What is the distance between c and d

OLga [1]

Answer:

Step-by-step explanation:

7 0

3 years ago

Elena randomly chooses a number from 1 to 10. What is the probability she chooses a number greater than 5?

zepelin [54]

ANSWER

$P(E)=\frac{1}{2}$

EXPLANATION

From the given information, Elena chooses a number from 1 to 10.

The sample space is

S={1,2,3,4,5,6,7,8,9,10}

n(S)=10

The numbers greater than 5 are:

E={6,7,8,9,10}

n(E)=5

The probability that, she chooses a number greater than 5 is:

$P(E) = \frac{n(E)}{n(S)}$

Substitute the values,

$P(E) = \frac{5}{10}$

$P(E) = \frac{1}{2}$

5 0

3 years ago

Please help with this!!! 25 points and i'll mark you brainliest!!! Show how you got answer!!!

HACTEHA [7]

Answer:

17.9°

Step-by-step explanation:

From trigonometry:

Opposite = 14

Adjacent = x

theta = 38°

hence;

tan theta = opposite/ adjacent

tan38° = 14/x

x = 14/tan38°

x = 17.9°

6 0

3 years ago

(8√2 - 5) (9√5 +6√10)<br> Simplify

salantis [7]

Answer:

42 (square root>) 10 + 51 (square root>) 5

Step-by-step explanation:

5 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago