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klemol [59]
4 years ago
7

Find the missing term.(x^12)^5 (X^-2)^9 (_____)^__=(x^40)^5

Mathematics
1 answer:
castortr0y [4]4 years ago
4 0
To answer this problem, we can use the power rule such that the result of the operations of the powers on the left side is equal to power on the right side. In this case, the right side's power is 200. On the left side, the tentative sum is 60 - 18 or equal to 42. Thus, the remaining exponent to be added on the left side is 158. Answer is x^158
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Dovator [93]

Answer:

$1236.67

Step-by-step explanation:

I = Prt

P = 26500

r = 0.07

t = 8/12 = 2/3

I = (26500)(0.07)(2/3)

I = 1236.67

6 0
3 years ago
80
dalvyx [7]

Answer:

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3 0
2 years ago
What is the simplest form of (3x^1/2)(4x^2/3)
ValentinkaMS [17]
When multiplying, we add exponents.

So first get a common denominator of 6.

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3 years ago
The radioactive substance polonium-210, with a half-life of 138.39 days, is present in tobacco. Suppose that the soot in an ex-s
Ksju [112]

Answer:

16.07 milligrams

Step-by-step explanation:

From the question,

Using the formula of radioactive decay,

R/R' = 2ᵃ/ᵇ..................... Equation 1

Where R = Original mass of the polonium-210, R' = Final mass of polonium-210 after decaying, a = Total disintegration time, b = half life of polonium-210.

Make R' the subject of the equation

R' = R/(2ᵃ/ᵇ)................ Equation 2

Given: R = 100 milligrams, a = 1 years = 365 days, b = 138.39 days

Substitute these values into equation 2

R' = 100/(2³⁶⁵⁰⁰/¹³⁸³⁹)

R' = 100/(6.222)

R' = 16.07 milligrams of plonium-210

3 0
3 years ago
3 dollar 8 dimes +1 dollar 2 quarters 5 pennies
zepelin [54]

Answer:

5.35

Step-by-step explanation:

1.55 +3.80 = 5.35

7 0
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