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1 year ago

4x² + 24x + 20 common factor =

Mathematics

1 answer:

adelina 88 [10]1 year ago

6 0

The common factor is 4

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Find the area under the curve y = 13/x3 from x = 1 to x = t. Evaluate the area under the curve for t = 10, t = 100, and t = 1000

zvonat [6]

Answer:

t = 10

$A = 32496.75$

t = 100

$A = 324999996.8$

t = 1000

$A=3.25\times 10^{12}$

Step-by-step explanation:

The area under the curve is calculated by using the following definite integral:

$A = \int\limits^t_ {1} \,{13\cdot x^{3}} dx$

$A = 13 \int\limits^t_1 {x^{3}} \, dx$

$A = \frac{13}{4}\cdot (t^{4}-1)$

Evaluated areas are presented below:

t = 10

$A = 32496.75$

t = 100

$A = 324999996.8$

t = 1000

$A=3.25\times 10^{12}$

8 0

3 years ago

I will give brainliest<br> !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

salantis [7]

Answer:

The horizontal line is the x axis

the vertical line is the y axis

The first number is always the number of the x axis

Example.

(6,9)

6 is in the x axis

9 is in the y axis

find the number 6 in the x axis (the horizontal one) and then go up until the number 9.

7 0

2 years ago

NEED HELP!!! WILL MARK BRAINLIEST!!!

Tanzania [10]

Answer:

RTA= (x-2)·(x-11/2)/(x-2)(x-4)= (you can simplify again if you want by eliminating both (x-2)

(x-11/2)/(x-4)

Step-by-step explanation:

Ok we need to simplify the expression so:

x^2+3x-10= Bhaskara formula=

-3(±√9-4·1·(-10))/2·1=

X1=(-3+7/2)--> X1=2(R)---> (X-R)--->X-2

X2=(-3-7)/2 --> X2=11/2(R)---> (X-R)--->X-11/2

x^2-6x+8= Bhaskara formula=

6(±√36-4·1·8)/2·1=

X1=(6-2)/2=2--> X1=2(R)---> (X-R)--->X-2

X2=(6+2)/2=2--> X2=4(R)---> (X-R)--->X-4

so, The simplify expression is

(x-2)·(x-11/2)/(x-2)(x-4)=

8 0

3 years ago

a long distance telephone company charges a rate of 8 cents per minute or 90 cent mininum charge per call, whichever is greater.

Oksi-84 [34.3K]

The cost of a 41 min call would be 328 cents. So, that would be 8 cents per minute, because the charge of the call is greater that 90 cents. Hope that helps!!

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3 years ago

10 POINTS!!! FULL ANSWER WITH FULL STEP BY STEP SOLUTION PLEASE. DO BOTH PARTS OF 3 AND ALL OF 4.

Temka [501]

See the attached picture for the answers:

6 0

3 years ago

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