Answer:
(a)

(b)


Step-by-step explanation:
Given

Solving (a): The pmf
This means that we list out the probability of each value of x.
To do this, we simply subtract the current probability value from the next.
So, we have:

The calculation is as follows:





The x values are gotten by considering where the equality sign is in each range.
means 
means 
means 
means 
means 
Solving (b):

This is calculated as:

From the given function


So:



This is calculated as:




Answer:
Amount pay after one year for compounded quarterly = Rs 5627.54
Step-by-step explanation:
Given as,
Manu took loan of Rs 5000 , So, Principal = Rs 5000
The rate of interest applied = 12% per annum compounded quarterly
The loan took for period of year = one
Now from the compounded method :
For compounded quarterly
Amount = principal 
Or, Amount = Rs 5000 
Or, Amount = 5000 
Or, Amount = 5000 × 1.1255
∴ Amount = Rs 5627.54
Hence , The amount which Manu pay after one year at 12% per annum compounded quarterly is Rs 5627.54 Answer
Answer:
15
Step-by-step explanation:
1 hr: 5
2 hr: 10
3 hr: 15
B)OPTION B only 1 is your answer.
Answer:
10/20
Step-by-step explanation:
10 times 20 is 200 which would give you 10/20
hope I did this right