Question

Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-7, -5), B(-7, 6),A(−7,−5),B(−7,6),A, left parenthesis, minus, 7, comma, minus, 5, right parenthesis, comma, B, left parenthesis, minus, 7, comma, 6, right parenthesis, comma C(-4, 6)C(−4,6)C, left parenthesis, minus, 4, comma, 6, right parenthesis, and D(-4, -5)D(−4,−5)D, left parenthesis, minus, 4, comma, minus, 5, right parenthesis.
Given these coordinates, what is the length of side CDCDC, D of this rectangle?

Answer 1

The length of side CD is equal to 11 units.

Given coordinates of rectangle are A(-7,-5), B(-7,6),C(-4,6) ,D(-4,-5)

We are require to find the length of side CD.

Rectangle is a two dimensional figure whose two opposite sides are equal to each other. Distance between two coordinates is the equal to length of a side.

We know that the distance means how far two points are located.

Coordinates of  A(-7,-5), B(-7,6),C(-4,6) ,D(-4,-5).

Distance=$\sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} }$ where ($x_{1} ,y_{2} )(x_{2} ,y_{2} )$ are the coordinates of two ends of a line.

CD=$\sqrt{(-5-6)^{2} +(-4+4)^{2} }$

=$\sqrt{11^{2}+0^{2} }$

=$\sqrt{121}$

=11 units.

Hence the length of side CD is 11 units.

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Question is wrong as it should be :

Coordinates of rectangle A(-7,-5), B(-7,6),C(-4,6) ,D(-4,-5) and find the length of CD.