Answer:
Average speed of go cart is 217.07 meters per minute.
Step-by-step explanation:
We are given the following in the question:
Length of straightway racetrack = 100 m
Diameter of semicircular end = 40 m
Radius =

Perimeter of racetrack =
Perimeter of semicircle + 2(Length of straightway) + Perimeter of semicircle

Speed =

Thus, average speed of go cart is 217.07 meters per minute.
Answer:
11.271
Step-by-step explanation:
just multiply
The answer is the third option choice
<h2>
Answer:</h2>
C = 2πr
r = C/2π ...(1)
A = πr²
A = π(C/2π)² = πC²/4π²
A = C²/4π.
<u>Correct choice</u> - [A] A = C²/4π.
In this
problem, the given values are:
x = average =
30.4
s = standard
deviation = 7.1
n = number of
samples = 25
Degrees of
freedom = n -1 =24
Using the
t-distribution table for a normal curve at 90% CI, we get t-crit:
t-crit = 1.711
Now the Margin
of Error (E) is calculated as:
E = t-crit*(s/
)
By substituting the known values into the equation:
E = 1.711 * (7.1/
)
E = +- 4.30
Therefore, the margin of error is 4.36. Hence, the commute time
is between 26.1 minutes and 34.7 minutes.
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