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Harman [31]
3 years ago
15

In a random sample of 25 ?people, the mean commute time to work was 30.4 minutes and the standard deviation was 7.1 minutes. ass

ume the population is normally distributed and use a? t-distribution to construct a 90?% confidence interval for the population mean ?. what is the margin of error of ??
Mathematics
1 answer:
seropon [69]3 years ago
7 0

In this problem, the given values are:

x = average = 30.4

s = standard deviation = 7.1

n = number of samples = 25

Degrees of freedom = n -1 =24

Using the t-distribution table for a normal curve at 90% CI, we get t-crit:

t-crit = 1.711

Now the Margin of Error (E) is calculated as:

E = t-crit*(s/ \sqrt{n})

By substituting the known values into the equation:

E = 1.711 * (7.1/ \sqrt{8})

E = +- 4.30

Therefore, the margin of error is 4.36. Hence, the commute time is between 26.1 minutes and 34.7 minutes.

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