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1 year ago

Use the Factor Theorem to determine whether x + 1 is a factor of P(x) = 2x³+4x²–2x−8.

Mathematics

1 answer:

Harman [31]1 year ago

5 0

Answer: $2x^2+2x-4-\frac{4}{x+1}$

Not a factor because there is a remainder.

Step-by-step explanation:

Let's use synthetic division to solve this..

-1 ║ 2 | 4 | -2 | -8

║ | -2| -2 | 4

║ 2 | 2| -4 | -4

$2x^2+2x-4-\frac{4}{x+1}$

PS: if anyone knows a better way to do a synthetic division chart please let me know.

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Zinaida [17]

Answer:

(0,12)

Step-by-step explanation:

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3 years ago

Solve the following ODE's: c) y* - 9y' + 18y = t^2

Nastasia [14]

Answer:

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

m² - 9 m + 18 = 0

m² - 3 m - 6 m+ 18 = 0

(m-3)(m-6) = 0

m = 3,6

C.F. = $C_1e^{3t}+C_2e^{6t}$

now calculating P.I.

$P.I. = \frac{t^2}{D^2 - 9D +18}$

$P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

hence the complete solution

y = C.F. + P.I.

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

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2 years ago

Evalue 3a -4b for a =a and b=6

katrin2010 [14]

Answer:

3a-4b

3a-4(6)

3a-24

Step-by-step explanation:

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3 years ago

What temperature Fahrenheit would give a temperature of 5 C?

GuDViN [60]

41 Fahrenheit is 5 Celsius

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3 years ago

Read 2 more answers

Rhombus ADEF is inscribed in △ABC such that the vertices D, E, and F lie on the sides AB , BC , and AC respectively. Find the si

Oksanka [162]

<h3>Answer:</h3>

3 11/15 cm

<h3>Step-by-step explanation:</h3>

AE is the angle bisector of ∠A, so divides the sides of the triangle into a proportion:

... BE:CE = BA:CA = 7:8

Then ...

... BE:BC = 7 : (7+8) = 7:15

ΔDBE ~ ΔABC, so DE = 7/15 × AC

... DE = 7/15 × 8 cm = (56/15) cm

... DE = 3 11/15 cm

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2 years ago