kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
Answer:
$1323.00
Step-by-step explanation:
A simple equation that can be used to figure this out is:
p*1.5*o=t
The variables mean:
p- hourly pay
o- hours worked overtime
t- total amount of money earned.
(Also, the 1.5 is always used to calculate overtime, no matter what job, unless otherwise specified, and as referred in the problem as "time and a half").
So, to finally work out this problem:
($14*1.5)*63=?
first, (14*1.5)= $21
($21*63)= $1323.
Answer:
2.28% probability that a person selected at random will have an IQ of 110 or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or higher?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or higher
30% of 47.50 is 14.25 so the amount payed the person payed in total would be 33.50
0.30 x 47.50 = 14.25
47.50 - 14.25 = 33.50