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Ilia_Sergeevich [38]
3 years ago
13

How many 0.4 liter glasses of water are contained in a 5.2 - liter pitcher? How do you find it out step by step?

Mathematics
1 answer:
Novay_Z [31]3 years ago
7 0
Let's start out with what we do know:
We have a 5.2L pitcher and 0.4L glasses and we want to know how many glasses we can fill with the 5.2L pitcher of water.

To answer that, we need to divide 5.2L by 0.4L in order to get the number of glasses (the number of 0.4L glasses that can go into a 5.2L pitcher)

So our equation will look like this:

n = \frac{5.2L}{0.4L} where n = number of glasses
so by doing that division we get:

n = 13
Notice that the L's cancel out leaving us with a plain number.

So a 5.2L pitcher of water can fill up 13 glasses!
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A crane lifts 50 Newtons 2 meters. How much work is done
Nikitich [7]

Answer:

100 Joules

Step-by-step explanation:

We use the definition of Work as the force applied multiplied by the distance the object was moved. In our case the force exerted is 50 N, over a distance of 2 meters, therefore:

Work = F * d = 50 N * 2 m = 100 N*m = 100 Joules

The SI unit for Newton times meter is called "Joule".

7 0
3 years ago
An elf ate 15 of your muffins. that was 5/8 of all of them. how many are left?
zavuch27 [327]

Answer: 9

Step-by-step explanation:

An elf ate 15 of your muffins and that was 5/8 of all of them. To get the number of muffins left goes thus:

We can first calculate the total number of muffins the person had. Let the total number of muffins be y. That means the elf ate 5/8 of y.

5/8 of y = 15

5/8 × y = 15

0.625 × y = 15

0.625y = 15

Divide both side by 0.625

0.625y/0.625 = 15/0.625

y = 24

The total amount of muffins is 24. Since the elf has eaten 15, the amount left will be: 24-15 = 9

6 0
3 years ago
Given: F(x) = 3x^2+1, G(x) = 2x - 3, H(X) = x<br> Find F(x) + G(x) =
weqwewe [10]

F(x)+G(x)=3x^2+2x-2.

Solution:

Given data: F(x)=3x^2+1 and G(x)=2x-3

To find F(x) + G(x):

Adding two functions which gives another function.

Substitute F(x) and G(x), we get

F(x)+G(x)=(3x^2+1)+(2x-3)

                    =3x^2+1+2x-3

                    =3x^2+2x-3+1

                    =3x^2+2x-2

F(x)+G(x)=3x^2+2x-2

Hence, F(x)+G(x)=3x^2+2x-2.

4 0
3 years ago
Remember to check for extraneous solutions
larisa86 [58]

Domain:v\neq0\\\\\dfrac{2}{v}+\dfrac{2}{3}=\dfrac{v-6}{3v}\\\\\dfrac{2\cdot3}{v\cdot3}+\dfrac{2\cdot v}{3\cdot v}=\dfrac{v-6}{3v}\\\\\dfrac{6}{3v}+\dfrac{2v}{3v}=\dfrac{v-6}{3v}\\\\\dfrac{6+2v}{3v}=\dfrac{v-6}{3v}\iff6+2v=v-6\qquad\text{subtract 6 from both sides}\\\\2v=v-12\qquad\text{subtract v from both sides}\\\\\boxed{v=-12}\to\boxed{A.}

3 0
3 years ago
Read 2 more answers
If θ is an angle in standard position whose terminal side passes through (3, 4), evaluate tan(1/2)θ.
aleksandr82 [10.1K]

The tangent half angle formula, one of several, is

\tan \dfrac a 2 = \dfrac{1 - \cos a}{\sin a}

We have θ is opposite 4 in the 3/4/5 right triangle so

\cos \theta = \dfrac{3}{5}

\sin \theta = \dfrac{4}{5}

\tan \dfrac{\theta}{2} = \dfrac{1 - 3/5}{4/5} = \dfrac{5-3}{4}=\dfrac{1}{2}

Answer: 1/2

This is actually pretty deep.  It says half the big acute angle in the 3/4/5 triangle is the small diagonal angle of the 1x2 rectangle.   Similarly, the small acute angle in 3/4/5 triangle is twice the small diagonal angle of the 1x3 rectangle.

7 0
3 years ago
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