Answer:
a. E = 11.90876 kcal
b. E = 23.81753 k cal
c. d = 209.93 ft
Explanation:
Knowing the relation between the energy and the food to realize how may energy do you need in each situation
a.
h = 100 ft / 2 = 50 ft
We = 0.75 lb * 100 * 9.8 = 735 J
E = We * h = 735 J * 50 ft = 36750 J
E to Kcal = 36750 J ⇒ 11.90876 k cal
E = 11.90876 kcal
b.
E = 735 * 100 ft = 73500 J
E to Kcal 73500 J ⇒ 23.81753 k cal
E = 23.81753 k cal
c.
Now to determine the distance with a candy of 50 kcal
d = 100 ft ⇒ 23. 81753 k cal
d ⇒ 50 k cal
d = ( 100 * 50 ) / 23.81753
d = 209.93 ft
Rubbing converts neutrons to protons, increasing the charge (APEX)
Answer:
Time period, ![T=1.11\times 10^{-8}\ s](https://tex.z-dn.net/?f=T%3D1.11%5Ctimes%2010%5E%7B-8%7D%5C%20s)
Explanation:
We have,
The frequency of an FM radio station is 89.3 MHz.
It is required to find the period of the wave.
The reciprocal of frequency is called time period of a wave. It can be given by :
![T=\dfrac{1}{f}\\\\T=\dfrac{1}{89.3\times 10^{6}\ Hz}\\\\T=1.11\times 10^{-8}\ s](https://tex.z-dn.net/?f=T%3D%5Cdfrac%7B1%7D%7Bf%7D%5C%5C%5C%5CT%3D%5Cdfrac%7B1%7D%7B89.3%5Ctimes%2010%5E%7B6%7D%5C%20Hz%7D%5C%5C%5C%5CT%3D1.11%5Ctimes%2010%5E%7B-8%7D%5C%20s)
So, the period of the wave is
.
It is an inelastic collision because the objects that collide move together after the collision, elastic objects would move separately post-collision