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coldgirl [10]
3 years ago
8

Problem: The frequency of an FM radio station is 89.3 MHz. Calculate its period. Part B: From the Library, select the general eq

uation to solve for period. Then click Done
Physics
1 answer:
vekshin13 years ago
5 0

Answer:

Time period, T=1.11\times 10^{-8}\ s

Explanation:

We have,

The frequency of an FM radio station is 89.3 MHz.

It is required to find the period of the wave.

The reciprocal of frequency is called time period of a wave. It can be given by :

T=\dfrac{1}{f}\\\\T=\dfrac{1}{89.3\times 10^{6}\ Hz}\\\\T=1.11\times 10^{-8}\ s

So, the period of the wave is 1.11\times 10^{-8}\ s.

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A girl running around a circular track of radius 200 m completes one
kondor19780726 [428]

Answer:

v = 2 m/s

Explanation:

First, we find the angular velocity of the girl by using the following formula:

Angular\ Velocity =\omega= \frac{Angular\ Distance\ Covered}{Time\ Taken}\\\\\omega = \frac{1\ revolution}{10\ min}\frac{1\ min}{60\ s}\frac{2\pi\ rad}{1\ revolution}\\\\\omega = 0.01\ rad/s

Now, for the average velocity of the girl we can use the following formula:

Average\ Velocity = V = r\omega\\V = (200\ m)(0.01\ rad/s)\\

where,

r = radius = 200 m

therefore,

<u>v = 2 m/s</u>

4 0
3 years ago
What is a zippper<br> awsedrftvgbhnjmk,l
lions [1.4K]

Answer:

a jacket closing mechanism a most useful tool to preserve and protect.

Explanation:

4 0
3 years ago
Read 2 more answers
1. Is the collision between the ball and the pendulum elastic or inelastic? Justify your answer by calculating the kinetic energ
Nitella [24]

Answer:

So energy is not conserved and inelastic shock

Explanation:

In the collision between a bullet and a ballistic pendulum, characterized in that the bullet is embedded in the block, if the kinetic energy is conserved the shock is elastic and if it is not inelastic.

Let's find the kinetic energy just before the crash

         K₀ = ½ m vₓ₀²

After the crash we can use the law of conservation of energy

Starting point. Right after the crash, before starting to climb

        Em₀ = K = ½ (m + M) v₂²

Final point. At the maximum height of the pendulum

       Em_{f} = U = (m + M) g h

Where m is the mass of the bullet and M is the mass of the pendulum

        Em₀ = Em_{f}

        ½ (m + M) v₂² = (m + M) g h

        v₂ = √ 2g h

Now we can calculate the final kinetic energy

       K_{f} = ½ (m + M) v₂²²

       K_{f} = ½ (m + M) (2gh)

The relationship between these two kinetic energies is

      K₀ / K_{f} = ½ m vₓ₀² / (½ (m + M) 2 g h)

      K₀ / K_{f} = m / (m + M)  vₓ₀² / 2 g h

We can see that in this relationship the Ko> Kf

So energy is not conserved and inelastic shock

5 0
4 years ago
A 1200-kg car accelerates it’s speed from 4 m/s to 10 m/s in 3 seconds. Find the car average speed , the car acceleration , the
dsp73

Answer:

Given: mass 1200kg

initial velocity: 4m/s

finial velocity: 10 m/s

time 3 sec

then

speed; initial velocity + final velocity/2

4+10/3

: 4.66m/s2

8 0
3 years ago
When released from rest: Potential energy = 100 J and Kinetic Energy would equal?
olga55 [171]

Answer:

0J

Explanation:

The kinetic energy would be zero. An object just released from rest will have no kinetic energy but the potential energy will be maximum.

Kinetic energy is the energy due to the motion of a body

Potential energy is the energy due to the position of a body.

  • The kinetic energy at the start will therefore be zero
  • All the energy is stored as potential energy.

Therefore, the kinetic energy is zero

5 0
3 years ago
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