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coldgirl [10]
3 years ago
8

Problem: The frequency of an FM radio station is 89.3 MHz. Calculate its period. Part B: From the Library, select the general eq

uation to solve for period. Then click Done
Physics
1 answer:
vekshin13 years ago
5 0

Answer:

Time period, T=1.11\times 10^{-8}\ s

Explanation:

We have,

The frequency of an FM radio station is 89.3 MHz.

It is required to find the period of the wave.

The reciprocal of frequency is called time period of a wave. It can be given by :

T=\dfrac{1}{f}\\\\T=\dfrac{1}{89.3\times 10^{6}\ Hz}\\\\T=1.11\times 10^{-8}\ s

So, the period of the wave is 1.11\times 10^{-8}\ s.

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The Moon has a radius of 1.7 × 106 m and a mass of 7.3 × 1022 kg. Find the gravitational field on the surface of the Moon.
Lisa [10]

Answer:

10.7*10^{6}

Explanation:

6 0
3 years ago
A pirate ship shoots a cannon towards an oncoming ship. The cannon ball has a mass of 25 kg and the ship has a mass of 2500 kg.
mars1129 [50]

Answer:

25 m/s in the opposite direction with the ship recoil velocity.

Explanation:

Assume the ship recoil velocity and velocity of the cannon ball aligns. By the law of momentum conservation, the momentum is conserved before and after the shooting. Before the shooting, the total momentum is 0 due to system is at rest. Therefore, the total momentum after the shooting must also be 0:

m_sv_s + m_bv_b = 0

where m_s = 2500 kg, m_b = 25 kg are masses of the ship and ball respectively. v_s = 0.25 m/s, v_b are the velocities of the ship and ball respectively, after the shooting.

2500*0.25 + 25*v_b = 0

25v_b = -2500*0.25

v_b = -2500*0.25/25 = -25 m/s

So the cannon ball has a velocity of 25 m/s in the opposite direction with the ship recoil velocity.

3 0
3 years ago
A student pulls a block over a rough surface with a constant force FP that is at an angle θ above the horizontal, as shown above
gizmo_the_mogwai [7]

Answer:

B.The force of friction between the block and surface will decrease.

Explanation:

The force of friction is given by

F_s = \mu N

where \mu is the coefficient of friction and N is the normal force.

When the student pulls on the block with force F_p at an angle \theta, the normal force on the block becomes

N  = Mg- F_psin(\theta)

and hence the frictional force becomes

F_s = \mu (Mg- F_psin(\theta)).

Now, as we increase \theta, sin(\theta) increases which as a result decreases the normal force Mg- F_psin(\theta), which also means the frictional force decreases; Hence choice B stands true.

<em>P.S: Choice D is tempting but incorrect since the weight </em>W=mg<em> is independent of the external forces on the block. </em>

6 0
3 years ago
Read 2 more answers
A bus travel with an average velocity of 60km/h. How long does it take to cover a distance of 500km​
Mnenie [13.5K]

Around 8 hours and 20 minutes

Explanation:

I divided 500 by 60 and got 8.3333333333 and i round it up to 8.20, so it is 8 hours and 20 minutes.

8 0
3 years ago
Do rolling down a grassy hill has kinetic energy or potential energy
Ann [662]

If you're moving, then you have kinetic energy.

If you're not at the bottom yet, then you still have
some potential energy left.

4 0
4 years ago
Read 2 more answers
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