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Studentka2010 [4]
3 years ago
6

why is the water cycle important to life on earth? the water cycle puts oxygen in the water. the water cycle moves water from pl

ace to place. the water cycle stores water for use in a time of drought. the water cycle makes water unusable by living things.
Physics
2 answers:
Leya [2.2K]3 years ago
8 0

Answer:

Without the the water on earth, nothing would be alive, no cavemen, no dinosaurs. Water is one of the most important component on earth so people can live. Water is everywhere. It goes through river, mountains, lakes, oceans even if your house. Without water human kind and any other would not be alive.

Explanation:

Without the the water on earth, nothing would be alive, no cavemen, no dinosaurs. Water is one of the most important component on earth so people can live. Water is everywhere. It goes through river, mountains, lakes, oceans even if your house. Without water human kind and any other would not be alive.

Katarina [22]3 years ago
7 0
Without the the water on earth, nothing would be alive, no cavemen, no dinosaurs. Water is one of the most important component on earth so people can live. Water is everywhere. It goes through river, mountains, lakes, oceans even if your house. Without water human kind and any other would not be alive.
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A 0.153 kg glider is moving to the right on a frictionless, horizontal air track with a speed of 0.700 m/s. It has a head-on col
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Answer:

3.1216 m/s.

Explanation:

Given:

M1 = 0.153 kg

v1 = 0.7 m/s

M2 = 0.308 kg

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M1v1 + M2v2 = M1V1 + M2V2

0.153 × 0.7 + 0.308 × -2.16 = 0.153 × V1 + 0.308 × V2

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0.153V1 + 0.308V2 = -0.55818. i

For the velocities,

v1 - v2 = -(V1 - V2)

0.7 - (-2.16) = -(V1 - V2)

-(V1 - V2) = 2.86

V2 - V1 = 2.86. ii

Solving equation i and ii simultaneously,

V1 = 3.1216 m/s

V2 = 0.2616 m/s

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3 years ago
In a physics lab, Asha is given a 10.7 kg uniform rectangular plate with edge lengths 67.3 cm by 53.5 cm . Her lab instructor re
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Answer:

I=2.6363\ kg.m^2

Explanation:

Given:

dimension of uniform plate, (0.673\times 0.535)\ m^2

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Now we find the moment of inertia about the center of mass of the rectangular plate is given as:

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where:

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I_{cm}=\frac{1}{12} \times 10.7\times(0.673^2+0.535^2)

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We know that the center of mass of the rectangular plane is at its geometric center which is parallel to the desired axis XX' .

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I=0.6591+10.7\times 0.4299^2

I=2.6363\ kg.m^2

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