Consider the given density curve.
1 answer:
The best approximation for the median is 3.6.
An illustration of a numerical distribution with continuous results is a density curve. A density curve is, in other words, the graph of a continuous distribution. This implies that density curves can represent continuous quantities like time and weight rather than discrete events like rolling a die (which would be discrete). As seen by the bell-shaped "normal distribution," density curves either lie above or on a horizontal line (one of the most common density curves).
For the given density curve, the area under the density curve is
A=(1/2)×5×(1/2)=5/4
now, for the median, the area on the left and the area on the right of the median.
Let the median be x, then
The area criteria we get
(1/2)x(x/10)=(5/4)/2
⇒x²=5*20/4=25/2
So, we get x=5/()=3.5 ≈ 3.6
Hence the required answer is option 3.6
Learn more about density curves here-
#SPJ10
You might be interested in
Lagrange multipliers:
(if 
)
(if )
(if 
)
In the first octant, we assume
, so we can ignore the caveats above. Now,
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
.
We also need to check the boundary of the region, i.e. the intersection of
with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force 
, so the point we found is the only extremum.
In the first octant, we assume
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
We also need to check the boundary of the region, i.e. the intersection of