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3 years ago

PLEASE HELP IMMEDIATELY! HURRY!

Mathematics

2 answers:

Fynjy0 [20]3 years ago

8 0

Answer:

5 * 5 * 5 * 5

Step-by-step explanation:

Use the rules of Indices.

5⁶⁻²

= 5⁴

Bezzdna [24]3 years ago

5 0

Answer:

Step-by-step explanation Bc 5 times 0 is nothing 5 times 3 is 15

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PLEASE HELP ASAP!!!

Dafna1 [17]

Answer:

Step-by-step explanation:

Any time you have compounding more than once a year (which is annually), unless we are talking about compounding continuously, you will use the formula

$A(t)=P(1+\frac{r}{n})^{(n)(t)}$

Here's what we have:

The amount after a certain time that she has in the bank is 4672.12; that's A(t).

The interest rate in decimal form is .18; that's r.

The number of times the interest compounds is 12; that's n

and the time that the money is invested is 3.5 years; that's t.

Filling all that into the formula:

$4672.12=P(1+\frac{.18}{12})^{(12)(3.5)}$ Simplifying it down a bit:

$4672.12=P(1.015)^{42}$ Raise 1.015 to the 42nd power to get

4672.12 = P(1.868847115) and divide to get P alone:

P = 2500.00

She invested $2500.00 initially.

6 0

3 years ago

A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life

alisha [4.7K]

Answer:

The null hypothesis is $H_0: \mu \leq 10$

The alternative hypothesis is $H_1: \mu > 10$

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

$H_0: \mu \leq 10$

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

$H_1: \mu > 10$

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that $\mu = 10$

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that $n = 45, X = 10.5, s = 1.8$

Then

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}$

$t = 1.86$

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

5 0

3 years ago

Can someone help me at least get this over with

tamaranim1 [39]

Here are the answers

5 0

3 years ago

The mean of Holly's first six math quiz scores was 75%. After taking the seventh quiz, her

lord [1]

The total of her first six quizzes is 75*6 = 450

Let her seventh score be x
The total of her seven quizzes be 450+x

Then, (450+x)/7 = 77
x = (77*7) - 450 = 89

Her seventh score is 89
x =

3 0

3 years ago

5, 7, 11, 19 Neither Geometric Arithmetic

dimaraw [331]

Arithmetic sequence

Explanation

An arithmetic sequence is a list of numbers with a definite pattern. If you take any number in the sequence then subtract it by the previous one, and the result is always the same or constant then it is an arithmetic sequence

Step 1

Let

$\begin{gathered} a_1=5 \\ a_2=7 \\ a_3=9 \\ a_4=11 \end{gathered}$ $\begin{gathered} a_2-a_1=7-5=2 \\ a_3-a_2=9-7=2 \\ a_4-a_3=11-9=2 \end{gathered}$

so, the difference is always the same, 2

Hence, the answer is a Arithmetic sequence

6 0

1 year ago