Answer:
There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555
Step-by-step explanation:
Given the functions:
f(x) = x² + 4x + 10
g(x) = -32x - 40
we want to find the points at which f(x) = g(x).
x² + 4x + 10 = -32x - 40
x² + 4x + 10 + 32x + 40 = 0
x² + 36x + 50 = 0
Using quadratic formula:
1. 4 (6 + 7) is the same as (4 • 6) + (4 • 7)
X = 4
2. 6 • 45 = 270
a. 270, (6 • 40) + (6 • 5) = 240 + 30 = 270
b. 210, (6 • 40) - (6 • 5) = 240 - 30 = 210
c. 270, (6 • 50) - (6 • 5) = 300 - 30 = 270
A. 270, C. 270
3. 6m + 7n + 5m - 3n, combine like terms, 6m + 5m = 11m, 7n - 3n = 4n
B. 11m + 4n
4. 2y<u>^3</u> - 4y^2 + y + y<u>^3</u>, exponents tell you what are like terms
C. 2y^3 and y^3
5. 4x<u>^3</u> - 3x^2 + x + 3x<u>^3</u>, combine like terms, then put in descending order
D. 7x^3 - 3x^2 + x
The third option is correct
X = 5
So 3x = 3(5) = 15
3x = 15
