Answer:
8 and 2/3 or 8.666666 forever
Step-by-step explanation:
Answer:
1+1=a a=solution
Step-by-step explanation:
Answer:
Step-by-step explanation:
If you call "5x-2x^2+1" an "equation," then you must equate 5x-2x^2+1 to 0:
5x-2x^2+1 = 0
This is a quadratic equation. Rearranging the terms in descending order by powers of x, we get:
-2x^2 + 5x + 1 = 0. Here the coefficients are a = -2, b = 5 and c = 1.
Use the quadratic formula to solve for x:
First find the discriminant, b^2 - 4ac: 25 - 4(-2)(1) = 25 + 8 = 33
Because the discriminant is positive, the roots of this quadratic are real and unequal.
-b ± √(discriminant)
Applying the quadratic formula x = --------------------------------
2a
we get:
-5 ± √33 -5 + √33
x = ----------------- = --------------------- and
2(-2) -4
-5 - √33
---------------
-4
Answer:
Step-by-step explanation:
z = 3
2y + z = 1
2y + 3 = 1 {substituting z =3}
2y = 1 -3
2y = -2
y = - 2/2
y = -1
2x +3y +2z = 13
2x + 3 * (-1) + 2*3 = 13 { {substituting z =3} and y = -1}
2x -3 + 6 =13
2x + 3 = 13
2x = 13 - 3
2x= 10
x = 10/2
x = 5
5^-4 / 5^3
= 5^-1
= 1/5
answer
<span>5^−1
</span><span>1 over 5</span>
