Question

Solve for x -ula1" title="\bold{x {}^{2} + 4x + 4 = 0}" alt="\bold{x {}^{2} + 4x + 4 = 0}" align="absmiddle" class="latex-formula">

ty! ~​

Answer 1

$\sf{\qquad\qquad\huge\underline{{\sf Answer}}}$

Let's solve for x ~

$\qquad \sf \dashrightarrow \: {x}^{2} + 4x + 4 = 0$

$\qquad \sf \dashrightarrow \: (x) {}^{2} + (2 \sdot x \sdot2) + (2) {}^{2} = 0$

The identity that must be used here is :

[ (a + b)² = a² + 2ab +b² ]

$\qquad \sf \dashrightarrow \: (x + 2) {}^{2} = 0$

$\qquad \sf \dashrightarrow \: (x + 2) = 0$

$\qquad \sf \dashrightarrow \: x = - 2$

So, the required value of x is -2

Answer 2

$\: \: \: \: \: \: \: \: \: \color{yellow} {\boxed{{ \colorbox{black} {\underline{ ANSWER}}}}}$

$\pmb{x^2-4x+4=0}$

$\longrightarrow\pmb{x^2-2x-2x+4=0}$

$\longrightarrow\pmb{x(x-2)-2(x-2) = 0}$

$\longrightarrow\pmb{(x-2)(x-2) = 0}$

$\longrightarrow\pmb{x = 2 }$