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2 years ago

Could I have some help please

Mathematics

1 answer:

solmaris [256]2 years ago

3 0

Since AB=AD, the triangle on the left is isosceles and has two 35 degree angles. Since the sum of all the interior angles is 180 deg,

x = 180 deg - 2(35 deg) = 110 deg (answer)

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ANSWER THIS ASAP DONT SEND A FILE AT ALL !! I NEED THE ANSWER QUICK HELPP ONLY ANSKER IF YOY REALLY KNOW!!

andre [41]

Answer:

...

Step-by-step explanation:

(x+8)(y+3)

8 0

2 years ago

Read 2 more answers

Which is traveling faster, a car whose velocity vector is 201 + 25), or a car whose velocity vector is 30i, assuming that the un

ioda

Answer with explanation:

For any object having the velocity vector as

$\overrightarrow{v}=v_x\widehat{i}+v_y\widehat{j}+v_z\widehat{k}$

the magnitude of velocity is given by

$|v|=\sqrt{v_x^2+v_y^2+v_z^2}$

For car 1 the velocity vector is

$\overrightarrow{v}_1=20\widehat{i}+25\widehat{j}$

Therefore

$|v_1|=\sqrt{20^2+25^2}\\\\\therefore v_1=32.0156units$

Similarly for car 2 we have

$\overrightarrow{v}_2=30\widehat{i}$

Therefore

$|v_2|=\sqrt{30^2}\\\\\therefore v_2=30.0units$

Comparing both the values we find that car 1 has the greater speed.

7 0

2 years ago

Short Response

garik1379 [7]

Answer:

(a)2(89x+84)

(b) $2(89x+84-x^2\pi)$

Step-by-step explanation:

The dimensions of the larger rectangular field are:

Length=5x + 12; Width = 9x + 14.

The dimensions of the smaller rectangular soccer field are:

Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

=Area of the larger rectangular field - Area of the Soccer Field

=(5x+12)(9x+14)-5x(9x)

=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain = $\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi$

Area of the Field that does not include the soccer field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

$=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)$

8 0

2 years ago

If y varies inversely as x, an d y = 12 when x = 6, what is K, the variation constant? A. 144 B. 72 C. 2 D. 1/3

Arlecino [84]

B is correct my friend

7 0

2 years ago

What is equivalent to 4/9(2n-3)

sp2606 [1]

4/9(2n)+4/9(-3)
(4x2/9)n+(4 x -3)/9
(8/9)n -12/9
8/9n-4/3

4 0

2 years ago