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AlladinOne [14]
3 years ago
13

Write an equation of the line that has a slope of 2 and contains the point (1, 1) in point-slope form.

Mathematics
1 answer:
exis [7]3 years ago
7 0
Point-slope form: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)

Data:
(1,1)
m=2

Therefore:
y-y₀=m(x-x₀)
y-1=2(x-1)    This is the equation of the line in point-slope form.

Answer.    y-1=2(x-1)
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The given line passes through the points (-4, -3) and (4,
drek231 [11]

Answer:

y = 2x + 11

Step-by-step explanation:

The first thing we need to do

is to find the slope of the line that passes through the points (-4,-3) and (4,1)

Mathematically, that would be;

m = y2-y1/(x2-x1)

where (x1,y1) = (-4,-3) and (x2,y2) = (4,1)

substituting these. values we have;

m = (1-(-3))/(4-(-4)) = 4/8 = 1/2 or 0.5

Now we are told this line is perpendicular to another line that passes through another point.

We can find the slope of this other line

Since both lines are perpendicular, the product of their slope is -1.

Thus , -0.5 * m = -1

m = -1/-0.5 = 2

So the slope of the other line is 2

Using the point-slope form;

y-y1= m(x-x1)

The point for the other line is (-4,3)

So the equation will be

y-3 = 2(x+4)

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3 years ago
The point LaTeX: \left(-1,\:5\right)( − 1 , 5 ) is the solution for the following system of equations
balu736 [363]
I think right is correct ( - 1, 5 )
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