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katrin [286]
4 years ago
12

quezlet: A survey of​ third- to​ twelfth-grade students with a sample size of 2026 found that they devoted an average of 1 hour

and 46 minutes per day to using entertainment media. Identify the population and the sample.
Mathematics
1 answer:
Maurinko [17]4 years ago
6 0

Answer:

Population is all students from grades 3-12.

Sample is the students who participated in the survey.

Step-by-step explanation:

Given : A survey of​ third- to​ twelfth-grade students with a sample size of 2026 found that they devoted an average of 1 hour and 46 minutes per day to using entertainment media.

To find : Identify the population and the sample.

Solution :

The population is defined as it contain all individuals which we want to collect the information.

So, the population consists of all third- to twelfth grade students.

Therefore, Population is all students from grades 3-12.

The sample is defined as a part of population of which information was actually collected.

So, the sample is only the respondents in the survey conducted in 2026.

Therefore, Sample is the students who participated in the survey.

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viva [34]

Answer: B. 3,276,000

Step-by-step explanation:

Given : A student number system for a county requires that the student number be 6 characters.

Number of digits (0,1,2,3,4,5,6,7,8,9)=10

Number of letters in English alphabet = 26

When repetition of things is not allowed then we use Permutations.

Number of permutations of m things taking n at a time =^mP_n=\dfrac{m!}{(m-n)!}

Similarly, Number of permutations of 10 numbers taking 4 at a time :

^{10}P_4=\dfrac{10!}{(6)!}=\dfrac{10\times9\times8\times7\times6!}{6!}=5040

Number of permutations of 26 letters taking 2 at a time :

^{26}P_2=\dfrac{26!}{(2)!}=\dfrac{26\times25\times24!}{24!}=650

Now, the possible number of numbers can be make = 5040\times650=3,276,000

Hence, the correct answer is options (b).

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Murljashka [212]

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Answer:

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Step-by-step explanation:

Given

\begin{array}{cccccc}x & {0} & {4} & {7} & {10} & {13} \ \\ y & {-5} & {-5} & {-5} & {-5} & {-5} \ \end{array}

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