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2 years ago

The graph shows the height of an elevator over a period of time.

Mathematics

1 answer:

natulia [17]2 years ago

6 0

C. Between E and F and between G and H the elevator could be travelling from a higher floor to a lower floor.

We have to justify all the options with respect to the graph :-

Option A : Between A and B, the elevator would be travelling from a lower floor to a higher floor. Also between C and D, the elevator would be travelling from a lower floor to a slightly higher floor.

So, this option is not correct.

Option B : Between B and C, the elevator wouldn't go higher. And also the same would happen in between D and E.

So, this option is not correct.

Option C : Between E and F, the elevator would be travelling from higher floor to lower and also between G and H.

So, this option is correct.

Option 4 : Between F and G, there would not have much changes. So it will be omitted.

So, this option is not correct.

Learn more about graph here :

brainly.com/question/4025726

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A grocery store is selling 6 cans of cat food for $3. Write and solve a multiplication equation to find the cost of a can of cat

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6 × $3 = $ 18 I hope I helped^_^

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3 years ago

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Multiply 5 yards 18 inches by 3? please show work

lesya692 [45]

Answer:

5 yards = 15 feet = 180 inches

Step-by-step explanation:

180 inches plus 18 inches = 198 inches

198 x 3 = 594 inches

594 inches = 49 feet 6 inches = 16 yards 1 foot 6 inches, or 16 yards 18 inches

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3 years ago

7. Find the value of x. Round the length to the nearest tenth. х 40° 11 cm

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3 years ago

Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 students, she finds 2 w

irina1246 [14]

Answer:

A 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus is [0.012, 0.270].

Step-by-step explanation:

We are given that Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 students, she finds 2 who eat cauliflower.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students who eat cauliflower

n = sample of students

p = population proportion of students who eat cauliflower

Here for constructing a 95% confidence interval we have used a One-sample z-test for proportions.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

Now, in Agresti and Coull's method; the sample size and the sample proportion is calculated as;

$n = n + Z^{2}__(\frac{_\alpha}{2})$

n = $24 + 1.96^{2}$ = 27.842

$\hat p = \frac{x+\frac{Z^{2}__(\frac{\alpha}{2}_) }{2} }{n}$ = $\hat p = \frac{2+\frac{1.96^{2} }{2} }{27.842}$ = 0.141

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.141 -1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } }$ , $0.141 +1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } }$ ]

= [0.012, 0.270]

Therefore, a 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus [0.012, 0.270].

The interpretation of the above confidence interval is that we are 95% confident that the proportion of students who eat cauliflower on Jane's campus is between 0.012 and 0.270.

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3 years ago

Describe 2 ways you could evaluate 37% of the sum of 27 3/5 and 15/9

miskamm [114]

First way is create an equation like this:
$0.37(27 \frac{3}{5}+ \frac{15}{9})$
and calculating it.
Second way is to find 37% of each number and then add it
$0.37*27 \frac{3}{5}$ + $0.37* \frac{15}{9}$
In both cases the result is 10.829

3 0

4 years ago