A kite is a quadrilateral in which two disjoint pairs of consecutive sides are congruent (“disjoint pairs” means that one side can’t be used in both pairs).
Then:
- Two disjoint pairs of consecutive sides are congruent by definition - QP≅QR and QR is not congruent to RS (one side can’t be used in both pairs);
- One diagonal (segment QS, the main diagonal) is the perpendicular bisector of the other diagonal (segment PR, the cross diagonal), so PM≅MR;
- The opposite angles at the endpoints of the cross diagonal are congruent, thus ∠QPS≅∠QRS.
- ∠PQR is not congruent to ∠PSR, because they are not angles at the endpoints of the cross diagonal.
Answer: correct options are A, B and E.
Answer: x only can have complex values, not real values.
x = -1/4 - 1/4i and x = -1/4 + 1/4 i
Explanation:
Finding the possible values of x in the expression given is solving the quadratic equation.
8x² + 4x = - 1
Rearrange the terms:
8 (x² + x/2) = - 1 ← common factor 8 in the left side
x² + x/2 = - 1/8 ← division property
x² + x/2 + 1/16 = - 1/8 + 1/16 ← addition property
(x + 1/4)² = -1/8 + 1/16 ← -factor the perfect square trinomial in the left side
(x + 1/4)² = - 1/16 ← add the fractions in the right side
x + 1/4 = (+/-) √ (-1/16) ← square roots on both sides
x + 1/4 = (+/-) (1/4)i ← complex solution
x = - 1/4 +/- 1/4i
x = - 1/4 - 1/4i and x = - 1/4 + 1/4 i ← answer
9514 1404 393
Answer:
F
Step-by-step explanation:
If the circle is tangent to the x-axis at 4, the center lies on the line x=4.
If the circle is tangent to the y-axis at 4, the center lies on the line y=4.
If the center of the circle is (x, y) = (4, 4) and it is tangent to the axes, then the radius is 4.
The standard-form equation of the circle centered at (h, k) with radius r is ...
(x -h)² +(y -k)² = r²
For the values (h, k) = (4, 4) and r = 4, the equation is ...
(x -4)² +(y -4)² = 16 . . . . . . matches choice F
Answer:
Here is what the graph will look like and here are some points..
Answer:
131
Step-by-step explanation:
