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Doss [256]
2 years ago
9

Which expression is equivalent to

sqrt{100}" align="absmiddle" class="latex-formula">
10
10²
50
50²
Mathematics
2 answers:
Simora [160]2 years ago
7 0

\huge\boxed{10}

\sqrt{100} means that you are looking for the number that, when multiplied by itself, produces 100. That number is 10, because 10\cdot10=100, meaning that \sqrt{100}=10.

Yuki888 [10]2 years ago
7 0
If you’re asked to solve the square root of 100, the answer is 10. If they want to know what of your choices would give you 100, then the answer would be 10 squared. 10*10=100 100/10=10
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Which numbers represent the lower quartile, the median, and the upper quartile of the following set of numbers?
kotegsom [21]

Answer:

Lower quartile: 85; median: 97; upper quartile 115.5

Step-by-step explanation:

4 0
3 years ago
Suppose the following number of defects has been found in successive samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6
Brut [27]

Answer:

Given the data in the question;

Samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.

a)

For a p chart ( control chart for fraction nonconforming), the center line and upper and lower control limits are;

UCL = p" + 3√[ (p"(1-P")) / n ]

CL = p"

LCL = p" - 3√[ (p"(1-P")) / n ]

here, p" is the average fraction defective

Now, with the 30 samples of size 100

p" =  [∑(6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.)] / [ 30 × 100 ]

p" = 234 / 3000

p" = 0.078

so the trial control limits for the fraction-defective control chart are;

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.078 + 3√[ (0.078(1-0.078)) / 100 ]

UCL = 0.078 + ( 3 × 0.026817 )

UCL = 0.078 + 0.080451

UCL = 0.1585

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.078 - 3√[ (0.078(1-0.078)) / 100 ]

LCL = 0.078 - ( 3 × 0.026817 )

LCL = 0.078 - 0.080451

LCL =  0 ( SET TO ZERO )

Diagram of the Chart uploaded below

b)

from the p chart for a) below, sample 28 violated the first western electric rule,

summary report from Minitab;

TEST 1. One point more than 3.00 standard deviations from the center line.

Test failed at points: 28

Hence, we conclude that the process is out of statistical control

Lets Assume that assignable causes can be found to eliminate out of control points.

Since 28 is out of control, we should eliminate this sample and recalculate the trial control limits for the P chart.

so

p" = 0.0745

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.0745 + 3√[ (0.0745(1-0.0745)) / 100 ]

UCL = 0.0745 + ( 3 × 0.026258 )

UCL = 0.0745 + 0.078774

UCL = 0.1532

LCL  = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.0745 - 3√[ (0.0745(1-0.0745)) / 100 ]

LCL = 0.0745 - ( 3 × 0.026258 )

LCL = 0.0745 - 0.078774

UCL = 0  ( SET TO ZERO )

The second p chart diagram is upload below;

NOTE; the red circle symbol on 28 denotes that the point is not used in computing the control limits

7 0
3 years ago
Please helppppppppppppppppppp
Vanyuwa [196]
6hrs = 360 minutes

360/7.5 = 48 bottles required

500g = 0.5kg

48x0.5 = 24 kg
24x 5 = 120p
5 0
3 years ago
Read 2 more answers
Is 300 mm greater than 3 cm
rewona [7]

Answer:

Yes

Step-by-step explanation:

There are 10 mm in 1 cm.

We have 300 mm, so let's convert this to cm by using a proportion:

\frac{10mm}{1cm} =\frac{300mm}{x} , where x is the number of cm in 300 mm.

Cross-multiplying, we get: 10x = 300, so x = 30 cm.

Clearly, 30 cm > 3 cm, so yes, 300 mm is greater than 3 cm.

Hope this helps!

4 0
3 years ago
Read 2 more answers
Two lines, A and B, are represented by equations given below: Line A: y = x − 4 Line B: y = 3x + 4 Which of the following shows
Ede4ka [16]
(-4,-8) because it satisfies both equations
5 0
4 years ago
Read 2 more answers
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