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3 years ago

Calculate the gradient of the straight line which joins A(2,-3) and B(6,9)

Mathematics

1 answer:

Pie3 years ago

5 0

Answer:

Gradient: m = 3

Step-by-step explanation:

m = change in y/change in x

m = $\frac{Y2-Y1}{X2-X1}$

m = $\frac{9-(-3)}{6-(2)}$

m = 12/4

m = 3

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Kruka [31]

Answer:

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Step-by-step explanation:

step 1

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substitute the values

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step 2

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we know that

If the distance from the center to point V is equal to the radius, then the point V lie on the circle

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A(-5,-8),V(-11,-6)

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$\sqrt{40}\ units< \sqrt{41}\ units$

The distance from the center to point V is less than the radius

therefore

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Aleonysh [2.5K]

Step-by-step explanation:

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1 year ago

Calculate the gradient of the straight line which joins A(2,-3) and B(6,9)​

Calculate the gradient of the straight line which joins A(2,-3) and B(6,9)