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nordsb [41]
3 years ago
13

15 minus the product of 5 times the difference of p minus 6

Mathematics
2 answers:
MrRissso [65]3 years ago
6 0
If i did this correctly it would be -5p +9
m_a_m_a [10]3 years ago
3 0
Written just as an expression it would be:

15-5(p-6)
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Please help me with the question below.
DaniilM [7]

Answer:

Alicia is correct

Step-by-step explanation:

The triangles are similar, then ratios of corresponding sides are equal, that is

left triangle to right triangle gives

\frac{r}{k} = \frac{s}{m}

Thus Alicia is correct. Jason has the incorrect sides on the second ratio

7 0
3 years ago
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Please help asap 18 pts + brainliest to right/best answer
saul85 [17]

Which two numbers add up to -29 and multiply to 100?

-25 and -4

Rewrite the expression

<u>(x - 25)(x - 4)</u>

7 0
3 years ago
What is the volume of the cylinder shown? Use 3.14 for pi. 4cm is the radius and 9cm is the height.
Irina18 [472]

Answer:

The formula is 4cm times 9cm which is 36cm. Then times that by pi which is 113.04. The answer is 113.04

Step-by-step explanation:

8 0
3 years ago
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Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
CAN SOMEONE HELP ME PLEASE???
lana66690 [7]

Answer:

Step-by-step explanation: First, you need to write all your data down from least to greatest. Next, count up all the numbers to see how many students. Then you want to find the mean which is average (add then divide). Median is the middle so you will x each number out till you get to the middle, and if the middle is 2 numbers, you find the average of them to find the median. Mode means most often. Range is highest minus lowest. And you can do the next 2.

4 0
3 years ago
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