Answer: 7 crayons
Step-by-step explanation:
To solve we first must find the total number of crayons available by adding up how many crayons are in each container.
56+12+96 = 160 crayons total
Next we take this number and divide it by 22 (the number of students in the class) to determine how many crayon each student gets
160 crayons/22 students = 7.272727 crayons per student
However, it's important to note that this number is not a whole number. We must then round down to the nearest whole number because students aren't given fractions of crayons.
7.272727 ==> 7 crayons per student
Answer:
133/143
Step-by-step explanation:
Let S be the sample space
Let E be the event of selecting three committee partners with at least one junior partner.
Partners in the law firm include:
Senior partners = 6
Junior partners = 7
Total partners = 13
n(S) = number of ways of selecting 3 partners from 13 = 13C3
n(S) = 13C3 = 13!/(10!3!) = (13x12x11)/(3x2x1) = 286
To get n(E) i.e least 1 junior partner in the selected committee, we may have:
(2 senior and 1 junior) or ( 1 senior and 2 junior) or (3 junior).
Therefore, the required number of way is given below:
= (6C2 x 7C1) + (6C1 x 7C2) + 7C3
= [(6x5)/2 x 7] + [6 x (7x6)/2] + [(7x6x5)/(3x2)]
= 105 + 126 + 35
n(E) = 266
Therefore, the probability P(E) that at least one of the junior partners is on the committee is given below:
P(E) = n(E) /n(S)
P(E) = 266/286
P(E) = 133/143
What is the average score? 79, 82, 85, 91, 97, 73, 88, 87, 85, 92, 90, 85, 86, 91, 94, 85, 92
alexdok [17]
79+82+85+91+97+73+88+87+85+92+90+85+86+91+94+85+92=1482 divided by 17 ( the amount of numbers) = 87.17
