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bogdanovich [222]
1 year ago
7

Carla is shopping for Storage Bags. At the grocery store, Brand A Storage Bags are priced $4.59 for 40 count, or Brand B Storage

Bags priced $3.99 for 30 count. Which is the better buy, Brand A or Brand B?
Mathematics
2 answers:
vichka [17]1 year ago
8 0

Answer:

Brand A

Step-by-step explanation:

Comment

The question is  one of finding out what the unit cost is.

Brand A: $4.59 has a count of 40

Brand B: $3.99 has a count of 30

Brand A

unit = 4.59 / 40 = 0.115

<em>Rounded: 0.12</em>

Brand B

unit = 3.99 / 30 = 0.133

<em>rounded: 0.13</em>

Brand A even with proper rounding is the better buy

hammer [34]1 year ago
8 0

Answer:

  Brand A

Step-by-step explanation:

The cost comparison can be done a variety of ways. The most formal of solutions will calculate the cost per bag for the two brands.

<h3>Informal solution</h3>

The cost for 10 bags of Brand B is $3.99/3 = $1.33. The cost for 10 more bags (40 bags instead of 30) of Brand A is $4.59 -3.99 = $0.60. This is less than the $1.33 it would cost to buy 10 more bags of Brand B, so ...

  Brand A is the better buy

<h3>Formal solution</h3>

The cost per bag is found by dividing the cost by number of bags:

  Brand A: $4.59 / (40 bags) = $0.11475 per bag

  Brand B: $3.99 / (30 bags) = $0.133 per bag

13¢ per bag is more than 11¢ per bag, so Brand A is the better buy.

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Answer:

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Step-by-step explanation:

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The profit function for the first version of the device was very similar to the profit function for the new version. As a matter
NeTakaya

Answer:

a) - Compressing the P(new) function by a scale of 0.5 about the y axis.

- Moving the P(new) function down by 104 units.

b) The two simplified functions for P(original)

-0.08x² + 10.8x – 200.

-0.16x² + 21.6x – 504.

Step-by-step explanation:

Complete Question

An electronics manufacturer recently created a new version of a popular device. It also created this function to represent the profit, P(x), in tens of thousands of dollars, that the company will earn based on manufacturing x thousand devices: P(x) = -0.16x² + 21.6x – 400.

a. The profit function for the first version of the device was very similar to the profit function for the new version. As a matter of fact, the profit function for the first version is a transformation of the profit function for the new version. For the value x = 40, the original profit function is half the size of the new profit function. Write two function transformations in terms of P(x) that could represent the original profit function.

b. Write the two possible functions from part a in simplified form.

Solution

The equation for the new profit function is

P(x) = -0.16x² + 21.6x – 400

At x = 40, the original profit function is half the size of the new profit function

First, we find the value of the new profit function at x = 40

P(x) = -0.16(40)² + 21.6(40) – 400 = 208

Half of 208 = 0.5 × 208 = 104

P(original at x = 40) = P(new at x = 40) ÷ 2

Since we are told that P(original) is a simple transformation of the P(new)

P(original) = P(new)/2 = (-0.16x² + 21.6x – 400)/2 = -0.08x² + 10.8x – 200 ... (eqn 1)

Or, P(original) = 104

-0.16x² + 21.6x – 400 = 104

P(original) = -0.16x² + 21.6x – 400 - 104 = -0.16x² + 21.6x – 504.

So, the two functions that are simple transformations of P(new) to get P(original) are

-0.08x² + 10.8x – 200

Obtained by compressing the P(new) function by a scale of 0.5 about the y axis.

And

-0.16x² + 21.6x – 504.

Obtained by moving the P(new) function down by 104 units.

Hope this Helps!!!

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