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2 years ago

In isosceles ∆ABC, points M and N belong to base

1 answer:

6 0

From the statements and reasons given below as regards the Isosceles Triangle, we have been able to prove that; ∆BAM ≅ ∆CAN

<h3>How to prove an Isosceles Triangle?</h3>

Isosceles Triangle means that two sides of the triangle are equal and also 2 angles are equal.

Now, we are told that triangle ABC is an Isosceles and as such, AB and AC are congruent.

We are given that BM and NC are congruent. Now, due to the fact that Triangle AMN is an isosceles triangle, it means that the sides AM and AN are congruent to each other.

Thus, from the proofs above and from the definition of the isosceles Triangle, we can say that triangles BAM and CAN are congruent.

Read more about Isosceles Triangle at; brainly.com/question/1475130

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What is the equation in slope intercept form for (2,5) (3,12)

kondaur [170]

Slope formula: y2-y1/x2-x1

= 12-5/3-2

= 7/1

= 7

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3 years ago

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

r-ruslan [8.4K]

The first thing you should do is to determine all the zeros, and you will have 7, -11, 2 + 6i, 2 - 6i.
After that you have to <span>subtract and (x) from every each zero that you have above, which means
</span> $7-x, 

 -11-x, 

2 + 6i-x,

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<span>And the last step is to multiply them together, and that's all you need!
</span> $(7-x)(-11-x)(2 + 6i-x)(2 - 6i-x)$
<span>I am pretty sure that everything hase become clear! Regards.</span>

6 0

3 years ago

Name a pair of complementary angles in the diagram above.

Tamiku [17]

Answer:

7&9

Step-by-step explanation:

Really, its just because, that's my explanation.

3 0

3 years ago

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago

Which expression is equivalent to (7 + 2i)(-3 - 4i)?

malfutka [58]

B -13 -34i

(7 + 2i)(-3 - 4i)
Take the 7 then times it buy the second bracket 7x(-3-4i) then take 2i from the first bracket and times it with the second bracket 2ix (-3-4i)

Then keep simplifying

5 0

2 years ago