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2 years ago

Find each angle measure

Mathematics

1 answer:

Lubov Fominskaja [6]2 years ago

7 0

Part A:<span> What is the mean of the data? Show your work. (4 points)</span>

Part B:<span> Use your answer from Part A to calculate the mean absolute deviation for the data. Show your work. (6 points)

</span>

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4(2x+3)=76 what does x equal

Akimi4 [234]

4(2x)=8x
4(3)=12
8x+12=75
-12
8x=63/8
x=7.89

6 0

2 years ago

Read 2 more answers

How to do this question? : (

Lostsunrise [7]

How to do what question

5 0

3 years ago

Given the relation x = y 4 − 9 y 2, identify the x- and y- axis intercepts.

Svetlanka [38]

The x-intercepts are $(0,0)$

The y-intercepts are $(0,0),(0,3),(0,-3)$

Explanation:

The relation is $x=y^{4} -9y^{2}$

To find the x-intercept, let us substitute $y=0$ in the equation $x=y^{4} -9y^{2}$ , we get,

$x=(0)^{4} -9(0)^{2} \\x=0$

Thus, the x-intercepts are $(0,0)$

To find the y-intercept, let us substitute $x=0$ in the equation $x=y^{4} -9y^{2}$ , we get,

$0=y^{4}-9 y^{2}$

let us switch sides and solving, we get,

$\begin{aligned}y^{4}-9 y^{2} &=0 \\y^{2}\left(y^{2}-9\right) &=0 \\y^{2} &=0, y^{2}-9=0\end{aligned}$

Taking square root,

$y=0$ and $\begin{aligned}y^{2}-9 &=0 \\y^{2} &=9 \\y &=\pm 3\end{aligned}$

Thus, the y-intercepts are $(0,0),(0,3),(0,-3)$

5 0

2 years ago

Plss

aleksley [76]

Answer:

$6,600

Step-by-step explanation:

231/0.035= 6,600

4 0

2 years ago

write the standard equation for the circle with the center at (4,1) and passing through the point (0,1)

Airida [17]

Without needing the distance formula

from 4,1 to 0,1, you move the "x" from 4 to 0, over the same "y" value of 1, so is just 4 units long, from the center to an endpoint, and the chord that stems from the center to an endpoint is the radius, so r = 4

$\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&4&1&4
\end{array}$

3 0

2 years ago