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BARSIC [14]
3 years ago
6

A nonuniform beam 4.50 m long and weighing 1.40 kN makes an angle of 25.0° below the horizontal. It is held in position by a fri

ctionless pivot at its upper right end and by a cable 3.00 m farther down the beam and perpendicular to it
The center of gravity of the beam is 2.00 m down the beam from the pivot. Lighting equipment exerts a 5.00-kN downward force on the lower left end of the beam. Find the tension T in the cable and the horizontal and vertical components of the force exerted on the beam by the pivot. Start by sketching a free-body diagram of the beam.

Physics
1 answer:
liubo4ka [24]3 years ago
7 0

Answer:

T = 7.64 kN

F_y = 0.52 kN(Downwards)

F_x = 3.23 kN (Towards Left)

Explanation:

As we know that beam is in equilibrium

So here we can use torque balance as well as force balance for the beam

Now by torque balance equation at the pivot we can say

F(4.50 cos\theta) + mg(2cos\theta) = T \times 3

As we know that

mg = 1.40 kN

F = 5 kN

so we will have

5 kN(4.50 cos25) + 1.40 kN(2 cos25) = 3 T

T = 7.64 kN

Now force balance in vertical direction

F + mg = Tsin65 + F_y

5 + 1.40 = 7.64 sin65 + F_y

F_y = 0.52 kN(Downwards)

Force balance in horizontal direction

F_x = T cos65

F_x = 7.64 cos65

F_x = 3.23 kN (Towards Left)

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How tall would a tower need to be if the period of a pendulum were 30. seconds
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Answer:

The displacement from point B to point E is 25.0 m left

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15. If an 800.-kg sports car slows to 13.0 m/s to check out an accident scene and the
goldfiish [28.3K]

The final combined velocity after the collision is 20.2 m/s

Explanation:

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This means that we can write the following equation:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 = 800 kg is the mass of the sport car

u_1 = 13.0 m/s is the initial velocity of the car (taking its direction as positive  direction)

m_2 = 1200 kg is the mass of the truck

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Re-arranging the equation and substituting the values, we find the velocity after the collision:

v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(800)(13)+(1200)(25)}{800+1200}=20.2 m/s

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3 years ago
A laser beam with a frequency of 180 Hz forms an 8 m standing wave with 10 nodes.
DIA [1.3K]

Answer:33

Explanation:

F = frequency

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w = wave lenght

v = wave velocity

L = distance wave traveled

First find wave length of laser

w = (2/(N))*(L)

w = (2/(10))*(8)

w = 1.6

then using (w), find velocity

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V = (1.6)*(108)

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Plug in V and the new frequency to solve for new node count

F = NV/2L

(600) = (N)*(288) / 2 * (8)

(N) = 33.33

there are 33 nodes

8 0
3 years ago
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