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Degger [83]
3 years ago
9

Our Milky Way galaxy is 100,000 ly in diameter. A spaceship crossing the galaxy measures the galaxy's diameter to be a mere 1 ly

. What is the speed of the spaceship relative to the galaxy? and How long is the crossing time as measured in the galaxy's reference frame?
Physics
1 answer:
krek1111 [17]3 years ago
3 0

Answer:

t= 100000.000005 years

Explanation:

Our Milky Way galaxy is 100,000 ly in diameter.

the galaxy's diameter to be a mere 1 ly.

We know that

L=L_0\sqrt{1-\frac{v^2}{c^2} }

L= 1 ly

L_0= 100,000 ly

1=100,000\sqrt{1-\frac{v^2}{c^2} }

v= 0.99999999995 c

so time t= \frac{d}{v} = \frac{100000c}{0.99999999995c}

t= 100000.000005 years

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Kobotan [32]

Explanation:

The given data is as follows.

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          v = 385 m/s

       sin (63.9^{o}) = 0.876

Now, we will calculate the magnitude of magnetic field as follows.

              B = \frac{F}{qv sin (\theta)}

                  = \frac{5.75 \times 10^{-16} N}{1.6 \times 10^{-19} C \times 385 m/s \times 0.876}

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3 years ago
If you doubled the load resistor in a Wheatstone bridge, the load current would not be half as much. Why not?
Fofino [41]
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6 0
3 years ago
An autotransformer is used to reduce the voltage of a 100-kilovolt amp, 480-volt secondary of an isolated type transformer, to s
tigry1 [53]

Answer:

42KVA

Explanation:

Given data

High Voltage (HV)= 480V

Low Voltage (LV)= 277V

Fo find

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Solution

To find the size of transformer here we use the co-ratio.The Co-ratio is given as:

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where

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Now put the values we get

Co- Ratio=(480-277)/480=.42

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5 0
3 years ago
. During a collision with a wall, the velocity of a 0.200-kg ball changes from 20.0 m/s toward the wall to 12.0 m/s away from th
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Answer:

106.7 N

Explanation:

We can solve the problem by using the impulse theorem, which states that the product between the average force applied and the duration of the collision is equal to the change in momentum of the object:

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F is the average force

\Delta t is the duration of the collision

m is the mass of the ball

v is the final velocity

u is the initial velocity

In this problem:

m = 0.200 kg

u = 20.0 m/s

v = -12.0 m/s

\Delta t = 60.0 ms = 0.06 s

Solving for F,

F=\frac{m(v-u)}{\Delta t}=\frac{(0.200 kg) (-12.0 m/s-20.0 m/s)}{0.06 s}=-106.7 N

And since we are interested in the magnitude only,

F = 106.7 N

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Answer:

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3 years ago
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