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Degger [83]
3 years ago
9

Our Milky Way galaxy is 100,000 ly in diameter. A spaceship crossing the galaxy measures the galaxy's diameter to be a mere 1 ly

. What is the speed of the spaceship relative to the galaxy? and How long is the crossing time as measured in the galaxy's reference frame?
Physics
1 answer:
krek1111 [17]3 years ago
3 0

Answer:

t= 100000.000005 years

Explanation:

Our Milky Way galaxy is 100,000 ly in diameter.

the galaxy's diameter to be a mere 1 ly.

We know that

L=L_0\sqrt{1-\frac{v^2}{c^2} }

L= 1 ly

L_0= 100,000 ly

1=100,000\sqrt{1-\frac{v^2}{c^2} }

v= 0.99999999995 c

so time t= \frac{d}{v} = \frac{100000c}{0.99999999995c}

t= 100000.000005 years

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Scilla [17]

Answer:

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

Explanation:

8 0
2 years ago
An object weighs 15N in air and 13N when completely
anastassius [24]

Answer:

The volume of water displaced = 0.204 m³

Explanation:

<em>From Archimedes' principle,</em>

<em>Upthrust = lost in weight = weight of water displaced.</em>

<em>U = W₁ - W₂..................... Equation 1</em>

<em>Where U = upthrust, W₁ = weight in air, W₂ = weight when completely submerged in water.</em>

<em>Given: W₁ = 15 N, W₂ = 13 N</em>

<em>Substituting these values into equation 1</em>

<em>U = 15 - 13 </em>

<em>U = 2 N</em>

<em>But,</em>

<em>Weight of water displaced = mass of water displaced. × acceleration due to gravity.</em>

<em>Mass of water displaced = weight of water displaced/ acceleration due to gravity.................... Equation 2</em>

Where: acceleration due to gravity = 9.8 m/s², weight of water displaced = 2 N

Substituting these values into equation 2

Mass of water displaced = 2/9.8

Mass of water displaced = 0.204 kg.

Also,

Volume of water displaced = mass of water displaced/ Density of water.............. Equation 3

Where Density of water = 1.0 kg/m³, mass of water displaced = 0.204 kg

Substituting these values into equation 3 above,

Volume of water displaced = 0.204/1

volume of water displaced = 0.204 m³

Therefore the volume of water displaced = 0.204 m³

<em />

8 0
3 years ago
A driver brings a car to a full stop in 2.0 s. If the car was
Dvinal [7]
Working displayed in the picture below, the answer is -11 m s^-2

7 0
3 years ago
By what factor must the amplitude of a sound wave be increased in order to increase the intensity by a factor of 9?a. 9 b. 2 c.
Marta_Voda [28]

Answer:

option D

Explanation:

given,

intensity\ \alpha \ (Amplitude)^2

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    I₁ = I₀

    I₂ = 9 I₀

now,

\dfrac{I_1}{I_2}=\dfrac{A_1^2}{A_2^2}

\dfrac{I_0}{9I_0}=(\dfrac{A_1}{A_2})^2

(\dfrac{A_1}{A_2})^2=\dfrac{1}{9}

\dfrac{A_1}{A_2}=\dfrac{1}{3}

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hence, amplitude increase with the factor of 3

so, the correct answer is option D

4 0
2 years ago
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GaryK [48]

Answer:

Explanation:

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5 0
3 years ago
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