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marysya [2.9K]
1 year ago
11

Apply the Distributive property:

d="TexFormula1" title=" \boxed{\sf 3(x-4)=2(-2x+1) }" alt=" \boxed{\sf 3(x-4)=2(-2x+1) }" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
jenyasd209 [6]1 year ago
5 0

Answer:

x = 2

Step-by-step explanation:

The left side would be (3x - 12)
The right side would be (-4x+2)

In an equation, 3x - 12 = -4x+2

Combine all the letters on the left and plain numbers on the right,

3x + 4x = 12 + 2

Note: When you transfer to the other side of the equal sign, the number will change its sign.

Simplify the 3x + 4x = 12 + 2,

                     7x = 14

                      x=\frac{14}{7}

                      x = 2

adell [148]1 year ago
5 0

⊱________________________________________________________⊰

Answer:

  • x=2

Step-by-step explanation:

\large\begin{gathered} \sf{Simplify \ using \ the \ distributive \ property:} \\ \sf{3(x-4)=2(-2x+1)} \\  \ \sf{3x-12=-4x+2} \\ \rm{Move \ 12 \ to \ the \ right, \ with \ the \ opposite \ sign} \\ \ \sf{ 3x=-4x+2+12} \\ \rm{Move \ -4x \ to \ the \ left, \ wth \ the \ opposite \ sign.} \\  \sf{3x+4x=14} \\  \rm{Collect \ the \ like \ terms} \\ \sf{7x=14} \\  \rm{Divide \ the \ entire \ equation \ by 7.} \\ \sf{\dfrac{7x}{7}=\dfrac{14}{7} \\ \sf{x=2}  \ \bigstar \end{gathered}

Done!!

⊱______________________________________________________⊰

<h3><em>Cαlligrαρɦγ</em></h3>
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Suppose that lithium calculator battery with a charge of 3 volts, actually has a voltage with uniform distribution between 2.93
Dmitrij [34]

Answer:

b. E(X) = 3.015, STDEV(X)= 0.049, P (X ≤ 2.98) = 0.2941

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean of the uniform probability distribution is:

M = \frac{a + b}{2}

The standard deviation of the uniform distribution is:

S = \sqrt{\frac{(b-a)^{2}}{12}}

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

Uniform distribution between 2.93 and 3.1 volts

This means that a = 2.93, b = 3.1. So

Mean:

M = \frac{2.93 + 3.1}{2} = 3.015

Standard deviation:

S = \sqrt{\frac{(3.1 - 2.93)^{2}}{12}} = 0.049

What is the probability that a battery has a voltage less than 2.98?

P(X \leq 2.98) = \frac{2.98 - 2.93}{3.1 - 2.93} = 0.2941

So the correct answer is:

b. E(X) = 3.015, STDEV(X)= 0.049, P (X ≤ 2.98) = 0.2941

6 0
3 years ago
Solve for x. Round to the nearest tenth, if necessary. 1.8 &amp; x
Valentin [98]

Answer:

x ≈ 1.4

Step-by-step explanation:

Using the sine ratio in the right triangle

sin50° = \frac{opposite}{hypotenuse} = \frac{RS}{RT} = \frac{x}{1.8} ( multiply both sides by 1.8 )

1.8 × sin50° = x , then

x ≈ 1.4 ( to the nearest tenth )

7 0
3 years ago
Please I need help I don't understand
mario62 [17]

Answer:

Step-by-step explanation:

from the graph of f(x)

when x=1,f(x)=0

or f(1)=0

when f(x)=2,x=2

for g(x)

when x=6,g(x)=16

or g(6)=16

when g(x)=18,x=32

for h(x)

when x=14

h(x)=27x-7

h(14)=27×14-7=7(27×2-1)=7(54-1)=7×53=371

h(x)=-493

27x-7=-493

27 x=-493+7=-486

3 x=-54

x=-18

for p(t)

when t=94

p(t)=24

p(94)=24

p(t)=67

t=31

8 0
3 years ago
1. Suppose you have a variable X~N(8, 1.5). What is the probability that you have values between (6.5, 9.5)
Natalija [7]

Answer:

0.6826 = 68.26% probability that you have values in this interval.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

X~N(8, 1.5)

This means that \mu = 8, \sigma = 1.5

What is the probability that you have values between (6.5, 9.5)?

This is the p-value of Z when X = 9.5 subtracted by the p-value of Z when X = 6.5. So

X = 9.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.5 - 8}{1.5}

Z = 1

Z = 1 has a p-value of 0.8413.

X = 6.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.5 - 8}{1.5}

Z = -1

Z = -1 has a p-value of 0.1587

0.8413 - 0.1587 = 0.6826

0.6826 = 68.26% probability that you have values in this interval.

7 0
2 years ago
The bottem half is the answers help pls for big brainnnnnn
vlabodo [156]

Answer:

C

Step-by-step explanation:

11 times 4 is 44 plus 5 is 49

4 0
2 years ago
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