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timama [110]
2 years ago
11

Help me please T^T Solve for m. m+1/3<-2 1/4

Mathematics
1 answer:
tia_tia [17]2 years ago
7 0

Answer:

answer is the second option  m<-2 7/12

Step-by-step explanation:

process:

convert -2 1/4 into an improper fraction

m+1/3 < -9/4

m <-9/4 -1/3

calculate the difference

m<-31/12

turn into a mixed fraction

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Final numeric grades in a certain course are normally distributed with a mean of 72.3 and a standard deviation of 6.4. The profe
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Answer:

The minumum numeric grade you have to earn to obtain an A is 81.29.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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In this problem, we have that:

\mu = 72.3, \sigma = 6.4

The professor curves the grades so that the top 8% of students will receive an A. What is the minumum numeric grade you have to earn to obtain an A?

The minimum numeric value is the value of X when Z has a pvalue of 1-0.08 = 0.92. So it is X when Z = 1.405.

So

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 72.3}{6.4}

X - 72.3 = 1.405*6.4

X = 81.29

The minumum numeric grade you have to earn to obtain an A is 81.29.

6 0
3 years ago
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