Ok so any number tat makes the denomenator 0 or makes the inside of a square root negative is restricted
we only have a denomenaor so
100v=0
v=0
therefor 0 is the excluded value since 0/0 doesn't make sense
Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
Answer:
check the length and the angles and check the height of it
substitute for your equation;
h(x) = f(x) - g(x)
h(x) = (3x + 2) - (-2x -4)
h(x) = 3x + 2 + 2x + 4 (minus and minus = addition)
h(x) = 3x + 2x + 2 + 4 (combine like terms)
h(x) = 5x + 6
Hope that helps! :D
Answer:
Step-by-step explanation:
<u>To make the given piecewise function continuous we need:</u>
- ax² - b = 6 and 5ax + b = 6 at x = 1
<u>It gives us the system:</u>
- a(1²) - b = 6 ⇒ a - b = 6
- 5a(1) + b = 6 ⇒ 5a + b = 6
<u>Sum of the two:</u>
- a - b + 5a + b = 6 + 6
- 6a = 12
- a = 2
<u>Then b is:</u>
