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kati45 [8]
4 years ago
5

Write this trinomial in factored form 6y^2 - 17y + 5

Mathematics
1 answer:
Neporo4naja [7]4 years ago
7 0

Answer:

(3y - 1)(2y - 5)

Step-by-step explanation:

Given

6y² - 17y + 5

Consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term.

product = 6 × 5 = 30 and sum = - 17

The factors are - 2 and - 15

Use these factors to split the y- term

6y² - 2y - 15y + 5 ( factor first/second and third/fourth terms )

= 2y(3y - 1) - 5(3y - 1) ← factor out (3y - 1) from each term

= (3y - 1)(2y - 5) ← in factored form

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8 0
3 years ago
2(x + y) + 9x +6y<br> Please answer!
wel

Answer:

11x + 8y

Explanation:

2(x+y)+9x+6y

Distribute:

=(2)(x)+(2)(y)+9x+6y

=2x+2y+9x+6y

Combine Like Terms:

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=(2x+9x)+(2y+6y)

=11x+8y

Answer:

=11x+8y

6 0
3 years ago
Circle O and circle P are congruent. What can you conclude from the diagram?
DENIUS [597]

Answer:

None of these.

Step-by-step explanation:

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3 0
3 years ago
HELP ASAP PLEASE!!! AND PLEASE SHOW WORK 1. 20% OF ____= 40 2. 30% OF ____=90
lesya692 [45]

Answer: 1. 200, 2. 300

Step-by-step explanation:

40 * 10/2 = 400/2 = 200

or this way:

40 = 20%

40/2 = 20

20 = 10%

20 * 10 = 200

——————————————

90 * 10/3 = 900/3 = 300

or this way:

90 = 30%

90/3 = 30

30 = 10%

30 * 10 = 300

8 0
3 years ago
Read 2 more answers
Solve logarithm equation please with steps.
fomenos
The first time I did it, I got an answer that's not one of the choices.  The second time
I did it, I got an answer that IS .  Here are both of my procedures.  If all you want is
the answer, look down below at the second one.  But if you could help me out, now
that you know how to do this stuff, please look at my first solution and tell me where
I messed up.  I can't find it.
=======================================================

Here's what the problem tells you:

D = 10 log ( ' I ' / 10⁻¹² )

D  = 60 . . . . . find ' I ' .

Here we go:

60 = 10 log ( ' I ' / 10⁻¹² )

Divide each side by 10 :

6 = log ( ' I ' / 10⁻¹² )

Raise 10 to the power of each side of the equation:

10⁶ = ' I ' / 10⁻¹²

Multiply each side by  10¹² :

10¹⁸ = ' I '     That's 10^18.  It looks bad, because that isn't one of the choices.

Let's try a slightly different procedure:

============================================

After substituting 10⁺¹² for I₀ , we're working with this formula:

           D = 10 log ( 'I' / 10⁺¹² )

Let's just look at the log part of that.

The log of a fraction is [ log(numerator) - log(denominator) ]

log of this fraction is [ log( 'I' ) - log(10⁻¹²) ]

But   log(10⁻¹²)  is just (-12) .

So the log of the fraction is [ log( 'I' ) + 12 ]

And the whole formula is now:

         D = 10 [ log( 'I' ) + 12 ]

60 = 10 [ log( 'I' ) + 12 ]

Divide each side by 10 :

6 = log( 'I' ) + 12

Subtract 12 from each side :

-6 = log ( ' I ' )

' I ' = 10⁻⁶

That's choice-'B' .

==================================================

I'm going to leave the first solution up there, in hopes that you, or one
of the many aces, experts, and geniuses that prowl this site constantly,
can weigh in and show me my blunder on the first attempt.


 





5 0
3 years ago
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