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1 year ago

What is the length of DE? A A 12 DXE A. 6 B. 8 C. 5 D. 7

Mathematics

2 answers:

Nastasia [14]1 year ago

8 0

Answer:

Step-by-step explanation:

these two triangles are similar

therefore corresping sides are proportionate

12/8=9/x

12x=72

x=72/12=6

Vikentia [17]1 year ago

5 0

Answer:

the answer is 6

Step-by-step explanation:

i hope this is helpful

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Please help i’ll mark brainliest!!!!!!

dangina [55]

Answer:

Width = 2x²

Length = 10

Step-by-step explanation:

The greatest common monomial factor of 14x² and 6x² is 2x² so the width is 2x².

Width = 2x²

Length = (14x² ÷ 2x²) + (6x² ÷ 2x²)

= 7 + 3

= 10

6 0

3 years ago

How to factorize 2^{n+1}+2^{n-1}?<br><br>I know the answer is 5(2^{n-1}), but how do i get there?

Elina [12.6K]

Answer:

steps below

Step-by-step explanation:

2ⁿ⁺¹ +2ⁿ⁻¹ = 2ⁿ⁻¹ (2² + 1) = 5*2ⁿ⁻¹

7 0

3 years ago

Evaluate the given expression if w = 6 and z = -3.

LenaWriter [7]

The answer will be 75
-3*-3*-3*-3=81
Z^4-w
81-6=75

5 0

3 years ago

Read 2 more answers

Bill made 5 gallons of fruit punch. If 1/4 of the punch was cranberry juice, how much cranberry juice did he use?

Temka [501]

1.25
---------------
.................

4 0

3 years ago

Read 2 more answers

(6-3(cube root of 6)/(cube root of 9)

MatroZZZ [7]

For this case we must simplify the following expression:

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}$

Multiplying the numerator and denominator by $(\sqrt [3] {9}) ^ 2$

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =$

We rewrite:

$\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =$

By properties of powers we have that:

$a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =$

We rewrite, moving the exponent within the radical:

$\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {9 ^ 2}} {9} =\\\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {81}} {9} =$

We can rewrite $3 * 3 ^ 3 = 81$

$\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {3 * 3 ^ 3}} {9} =$

We simplify:

$\frac {(6-3 \sqrt [3] {6}) * 3 \sqrt [3] {3}} {9} =$

We apply distributive property:

$\frac {18 \sqrt [3] {3} -9 \sqrt [3] {18}} {9} =$

Simplifying we finally have:

$2 \sqrt [3] {3} - \sqrt [3] {18}$

Answer:

$2 \sqrt [3] {3} - \sqrt [3] {18}$

5 0

3 years ago