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3 years ago

Two classmates are preparing research papers and are organizing their information on index cards.

1 answer:

5 0

So proprtion
A.
keiko=3:5
will=4:6
make as fractions
3/5 and 4/6
simplify
3/5=3/5
4/6=2/3
3/5 not equal to 2/3, so NOT similar

B. Joel=12:8 conver to fractions
12/8=6/4=3/2
this is similar to 2/3 since the cards can be flipped to be similar
Joel's card is similar to will's card

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What term best describes the graph of y=-2

sesenic [268]

Answer:

It would be constant.

Step-by-step explanation:

Since there is no x value, the line will have no slope and just be horizontal about y= -2.

6 0

2 years ago

Suppose f(x) = 1/4 over the range a ≤ x ≤ b, and suppose P(X > 4) = 1/2.

Anettt [7]

Answer:

a=2

b=6

Step-by-step explanation:

Assuming a uniform distribution and that a ≤ x ≤ b, if f(x) = 1/4, then:

$f(x) =\frac{1}{4}=\frac{1}{b-a}\\b-a = 4$

If P(X > 4) = 1/2, then:

$\frac{1}{2} = 1-(\frac{x-a}{b-a})=1-(\frac{4-a}{4})\\a-4+4 =\frac{1}{2}*4\\ a=2\\b=4+a\\b=6$

The values for a and b are, respectively, 2 and 6.

3 0

3 years ago

Why is the number of operators per shift multiplied by approximately 4.5 to obtain the total number of operators required to run

4vir4ik [10]

I believe you meant "why is the number of shifts multiplied by approximately 4.5 to obtain the total number of operators required to run the plant"

Answer and Explanation:

There are 3 shifts per day, 49 weeks per year and 5 shifts per operator per week

To get total number of operators required to run the plant, we multiply number of shifts in a year by number if operators per shift.

49 weeks×5 shifts= 245 shifts per operator per year

365×3 shifts= 1095 shifts per year

1095/245=4.5 operators per shift

total number of operators required to run the plant(per day) = 4.5×3= 13.5 approximately 14

total number of operators required to run the plant(per year) =4.5×1095=4927.5 approximately 4928

3 0

3 years ago

Find the quadratic function y=f(x) whose graph has a vertex (−3,4) and passes through the point (−7,0). Write the function

olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola. The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front. So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex: x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

-4 = 16a so

$a=-\frac{1}{4}$