Answer: b
Step-by-step explanation:
Answer:
a) one solution(x = 9)
b) no solution
c) infinite solutions
Step-by-step explanation:
a) To solve this equation, we can add 4 on both sides in order to isolate x:
x - 4 =5
+ 4 + 4
x = 9
Since x equals 9, that counts as only one solution, as there is only one value of x that makes the equation true.
b) We start by subtracting 2x from both sides to combine the variable terms:
2x - 6 = 2x + 5
-2x -2x
-6 = 5
The statement, -6 = 5 is never true and it is not dependent on the value of x. This means there are no solutions to this equation.
c) We can start by subtracting 3x from both sides to combine the terms with x:
3x + 12 = 3x + 12
-3x -3x
12 = 12
The statement above is always true, and no matter the value of x, it will always be true. This means there are infinite solutions to the equation.
It's just AAAAA, no other answers. So just check A
Answer: There was 5/8 of a foot of board left.
Step-by-step explanation:
Step 1. We need to subtract 1/4 from 7/8. To do this make it where both fractions have the same denominator.
Step 2. The easiest way to do this is to multiply 1/4 by 2.
1/4*2/2=2/8.
Step 3. Now all you got to do is subtract 2/8 from 7/8.
7/8-2/8= 5/8.
Answer:
1) is not possible
2) P(A∪B) = 0.7
3) 1- P(A∪B) =0.3
4) a) C=A∩B' and P(C)= 0.3
b) P(D)= 0.4
Step-by-step explanation:
1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4
2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by
P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7
P(A∪B) = 0.7
3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3
4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then
P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3
the probability for the event D=a student has exactly one of the cards is
P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4
