All categories

3 years ago

If the volume of a sphere is 972(3.14) cubic inches what is the radius- a. 7 icnches b. 9 inches c. 108 inch d. 324 inch

2 answers:

7 0

The volume of a sphere is $V=\frac{4}{3}\pi r^3$ . Our volume is given to us as $972\pi$ , so we fit that into the equation to solve for the radius. It looks like this when we do that. It doesn't matter that we use the pi symbol instead of the 3.14 value, because they cancel each other out anyway. Watch. $972\pi =\frac{4}{3}\pi r^3$ . First thing we will do is multiply both sides by 3 to get rid of the fraction. $2916\pi =4\pi r^3$ . Now we divide both sides by 4pi. The pi's will cancel each other out, leaving us with $729=r^3$ . Now we take the cubed root of 729 on our calculators to get that r = 9. Choice b.

SCORPION-xisa [38]3 years ago

4 0

Hi!

To find the volume of a sphere you have to solve an equation, pretty easy once you get the hang of it!

The equation you will need is, V = $\frac{4}{3}$ $\pi$ r³

The first part is 4/3 multiplied by $\pi$ by the radius (half the diameter)

So since we do not have the radius, we have to insert the volume in the V variable and solve from there,

<span>972
so that divided by 4/3 (3.14) should get you your answer, which is 9
Hope I helped

</span>

You might be interested in

Rewrite 0.169 in expanded form using powers of ten. A) (1×103) + (6×102) + (9×101) B) (1×101) + (6×102) + (9×103) C) (1×10-1) +

lubasha [3.4K]

That would be C....(1 x 10^-1) + (6 x 10^-2) + (9 x 10^-3)

5 0

3 years ago

In Fig. 6.28, find the value of x and y and then show that AB || CD.

poizon [28]

Answer:

Maybe 180° -50° = 130°

So I think x= 130°

Step-by-step explanation:

My opinion though

6 0

2 years ago

students are encouraged to exercise at least 2 1/2 hours a week. Hector exercises about the same number of hours each week. duri

Natasha2012 [34]

Answer:

On average, he exercises 2.875 hours per week.

Step-by-step explanation:

Just do 11 1/2 (11.5) divided by 4, and you get your answer of 2.875 hours per week.

6 0

2 years ago

If n(A-B)=18,n(AuB)=70 and n(AnB)=25 then find n(B)

svp [43]

n(A-B) denotes elements which are in A but not in B

n(Au B) denotes elements in A and B

n(AnB) denotes elements that are common in A and B

Now I will add one more set

n(B-A) which denotes elements in B but not in A

So, n(AuB) = n(A-B) + n( B-A) +n(AnB)

70 = 18 +n(B-A) + 25

70 = 43 + n(B-A)

n(B-A) = 70-43

n(B-A) = 27

So, n(B) = n( B-A) + n( AnB)

= 27+25

= 52

4 0

3 years ago

The diagram shows a 5 cm x 5 cm x 5 cm cube.

mylen [45]

Answer:

~8.66cm

Step-by-step explanation:

The length of a diagonal of a rectangular of sides a and b is

$\sqrt{a^2+b^2}$

in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:

$\sqrt{\sqrt{a^2+b^2}^2 + c^2} = \sqrt{a^2+b^2+c^2}$

Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths $a_1, a_2, a_3, \ldots, a_n$ is

$\sqrt{a_1^2 + a_2^2 + a_3^2 + \ldots + a_n^2}$

So the solution here is

$\sqrt{(5cm)^2 + (5cm)^2 + (5cm)^2} = \sqrt{75cm^2} = 5\sqrt{3cm^2} \approx 5\cdot 1.732cm = 8.66cm$

5 0

2 years ago

Read 2 more answers