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Savatey [412]
3 years ago
6

Jim made 14 L of lemonade for his party. His guests drank 4500 mL

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0
14L = 14000 mL. So subtract 14000 by 4500 to get a sum of 9500 mL
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What is 3x +2 (5x -7) simplified
Anvisha [2.4K]

Answer:

16x - 14

Step-by-step explanation:

3x + 10x + -14 + 3x

16x - 14

7 0
4 years ago
3a=1<br> What is a equal to?
miskamm [114]

Answer:

1/3

Step-by-step explanation:

3a = 1

/3    /3

a = 1/3

6 0
3 years ago
Read 2 more answers
Solve the equation in two different ways. Choose one method of solving in detail 5x+7(x+1) = 5x - 21
frozen [14]

Answer:

METHOD 1:

5x+7(x+1)=5x-21

5x+7x+7=5x-21

12x+7=5x-21

12x-5x=-21-7

7x=-28

x=28/7

x=4

METHOD 2:

5x+7(x+1)=5x-21

5x+7(x+1)=5x-21-5x

7(x+1)=-21

7x+7=-21

7x=-28

x=4

Step-by-step explanation:

METHOD 1:

5x+7(x+1)=5x-21

5x+7x+7=5x-21

12x+7=5x-21

12x-5x=-21-7

7x=-28

x=28/7

x=4

METHOD 2:

5x+7(x+1)=5x-21

5x+7(x+1)=5x-21-5x

7(x+1)=-21

7x+7=-21

7x=-28

x=4

6 0
3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
Find the area of a parallelogram with these dimensions.
aev [14]
The area is 14! hope this helps
3 0
3 years ago
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